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tamaranim1 [39]
3 years ago
9

What is the product of the expression (-2.2)(1.5)(-4.2)

Mathematics
2 answers:
Nataliya [291]3 years ago
8 0

Answer:

13.86

Step-by-step explanation:

(-2.2)(1.5)(-4.2) =

Use a calculator. Start with -2.2 * 1.5.

= (-3.3)(-4.2)

= 13.86

jok3333 [9.3K]3 years ago
5 0

Answer:13.86

Step-by-step explanation:

((−2.2)(1.5))(−4.2)

=(−3.3)(−4.2)

=13.86

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Marco is making a kite, using sticks for its diagonals. One stick is 2 feet long and the other is 3 feet long. How much material
Marat540 [252]

Answer:

Marco will need 3\ ft^{2} of material to make the kite

Step-by-step explanation:

we know that

To know how much material Marco will need to make the kite, the area must be calculated.

Remember that the area of the kite is equal to

A=\frac{1}{2}[d1*d2]

where

d1 and d2 are the diagonals of the kite

we have

d1=2\ ft

d2=3\ ft

substitute

A=\frac{1}{2}[2*3]=3\ ft^{2}

3 0
3 years ago
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What is the remainder when the polynomial 6x^2 + 11x - 3 is divided by x + 2?​
Firlakuza [10]

Answer:

Same

Step-by-step explanation:

Same tayo ng question

4 0
4 years ago
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The answer should be b
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3 years ago
Two unidentified flying discs are detected by a receiver. The angle of elevation from the receiver to each disc is 39.48 degree.
lys-0071 [83]

Answer:

The answer is "298.83 m"

Step-by-step explanation:

Its gap from its transmitter from each disc comprises of 2 triangles. Its horizontal segment via disc to vertical, and longitudinal segment. Disk height, h, is parallel to a horizontal disc Wink including its line across recipient to disc or horizontal 39. 48^{\circ}

\to 39. 48^{\circ}  = \frac{h_1}{826 \ m}\\\\   \to 826\ m (\ sin 39. 48^{\circ} ) = h_1\\\\ \to 525.18 = h_1\\\\

if:

\to \sin 39. 48^{\circ} = \frac{h_2}{1.296 \ km}\\\\ \to  \sin 39. 48^{\circ} (1296 \ m) = h_2\\\\  \to  824.01 = h_2\\\\\to                        h_2  - h_1 = 824.01 - 525.18\\\\

                  = 298.83 \ m

4 0
3 years ago
A grain silo has the shape of a right circular cylinder surmounted by a hemisphere. If the silo is to have a volume of 505π ft3,
Romashka-Z-Leto [24]

Answer:

radius   x  = 3 ft

height   h = 23,8  ft

Step-by-step explanation:

From problem statement

V(t)  = V(cylinder) + V(hemisphere)

let x be radius of base of cylinder (at the same time radius of the hemisphere)

and h the height of the cylinder, then:

V(c)  = π*x²*h       area of cylinder = area of base + lateral area

                                              A(c)  = π*x²  +   2*π*x*h

V(h) = (2/3)*π*x³   area of hemisphere   A(h)  =   (2/3)*π*x²

A(t)  =  π*x²  +   2*π*x*h +   (2/3)*π*x²

Now A as fuction of x    

total volume   505  = π*x²*h  +  (2/3)*π*x³

h = [505 - (2/3)* π*x³ ]  /2* π*x    

Now we have the expression for A as function of x

A(x) =  3π*x² + 2π*x*h     A(x) = 3π*x² + 505  - (2/3)π*x³

Taking derivatives both sides

A´(x) =  6πx -  2πx²              A´(x) =  0         6x  - 2x²  = 0

x₁  =  0  we dismiss

6 - 2x = 0

x = 3     and   h = [505 - (2/3)* π*x³]/2* π*x

h  =  (505 - 18.84) / 6.28*3

h  = 23,8  ft

7 0
3 years ago
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