Answer:
Very tough question. Oh I was just kidding but first increase points then I will answer
Answer:
So, y = x^2 is a quadratic equation, as is y = 3x^2 + x + 1. All of these are polynomial functions of degree 2. Often you will be given the quadratic ...
Answer:
-1,5 \ 1,-3 \2,-4 \4,0\
Step-by-step explanation:
Given=
length of the segment AD is 28 cm
distance between the midpoints of segments AB and CD is 16 cm
find out length of BC
To proof
AD = 28 cm
let the midpoint of the AB is E.
let the midpoint of the CD is F.
E & F are the midpoints i.e these points divide AB & CD in two equal parts.
Let BC = z
Let AE = EB = x ( E is midpoint)
Let CF = FD = y (F is midpoint)
the equation becomes
2x + 2y + z = 28
x + y + z = 16
mulitipy above equation by 2
we get
2x + 2y + 2z = 32
thus solving the equations
2x + 2y + 2z = 32
2x + 2y + z = 28
we get
z = 4 cm
i.e BC = 4 cm
Hence proved
Answer:
67.38°
Step-by-step explanation:
The diagonals of a rhombus intersect at their midpoints and make a right angle. They also divide the angles of the rhombus in two equal angles.
So, to find the acute angle of the rhombus, we can use the tangent relation of half this angle in the small triangle made when drawing the diagonals:
tan(angle/2) = 4 / 6
tan(angle/2) = 0.666
angle/2 = 33.69
angle = 67.38°
So the acute angle of the rhombus is 67.38 degrees.
Please check the image attached for better comprehension.