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andrew-mc [135]
3 years ago
12

Math problem I need help pleaseeee ASAP

Mathematics
1 answer:
kondor19780726 [428]3 years ago
3 0

Answer:

Step-by-step explanation:

2y + 7 - 4y = 15 - 2y - 8

-2y + 7 = 7 - 2y

-3n - 2 = 4n - 2 - 7n

-3n - 2 = -3n - 2

You might be interested in
The range of the function y = 2cos x is -2 ≤ y ≤ 2.
Vadim26 [7]

<u>Answer:</u>

The range of the function y = 2cos x is -2 <y < 2 .

<u>Step-by-step explanation:</u>

We know that cos (0) = 1 and cos (π) = - 1 are the two extreme values which cos x assume when x ∈ R and it is also that cos (x) is a continuous periodic function with period 2π when x ∈ R ,

since ,

cos (x + 2π) = cos x

So, the range of the  function y = 2cos x is -2 <y < 2 .

7 0
3 years ago
The reliability of a piece of equipment is frequently defined to be the probability, P, that the equipment performs its intended
Sergio [31]

Answer:

a. y=1

b. Mean= 0.5; variance=0.5

c. In the first instance, the probability that p > 0.95 would mean that we are looking for the area of the rectangle with a height of 1 between 0.95 and 1, which implies it has length 0.05.

Therefore, the area is length × height, which is 0.05 ×1 = 0.05.

Second case, the probability that p is less than 0.95 would then be one minus the probability that p is greater than 0.95, so 1 - 0.05 = 0.95

D. a horizontal line at 20 between 0.90 and 0.95, and will be zero outside of this range.

Step-by-step explanation:

With the use of probability distribution, the probability that the equipment performs has a uniform distribution with minimum 0 and maximum 1.

a) The graph of the probability distribution will be 0 outside of the range of 0 to 1, so therefore y = 0. Inside the interval from 0 to 1, it will be constant (which is a horizontal line) with height 1÷(1-0) = 1, therefore y = 1.

b) The mean of the uniform is (maximum+minimum)/2.

Therefore, (1+0)/2 = 1/2 or 0.5.

The variance of the uniform is

(maximum-minimum)^2/12,

so (1-0)^2/12 = 1/12.

c) Since the probability distribution is rectangular, you can find probabilities by recalling the area of a rectangle which is: area = length × breadth.

In the first instance, the probability that p > 0.95 would mean that we are looking for the area of the rectangle with a height of 1 between 0.95 and 1, which implies it has length 0.05.

Therefore, the area is length × breadth, which is 0.05 ×1 = 0.05.

In the second case, the probability that p is less than 0.95 would then be one minus the probability that p is greater than 0.95, so 1 - 0.05 = 0.95.

d) If it is known that p is between 0.90 and 0.95, without the value, then we would assume that p has a uniform distribution between 0.90 and 0.95 since p originally had a uniform distribution.

In this case,

f(p) =

1/(0.95-0.90) = 20, 0.90 < p < 0.95,

0, otherwise.

In a nutshell, this function will have a horizontal line at 20 between 0.90 and 0.95, and will be zero outside of this range.

6 0
3 years ago
Determine the domain and range of the given function.<br> The domain is<br> The range is
astra-53 [7]
What is the function?
6 0
3 years ago
Read 2 more answers
Don't know this please help me give brainly
Sergio039 [100]
Just pick random it’s helpful
6 0
3 years ago
I NEED HELP PLSSSSSSSS
AVprozaik [17]

Answer:

X >>>>> Y

–1 >>>> 16

0 >>>>> 8

1 >>>>> 4

2 >>>>> 2

3 >>>>> 1

Step-by-step explanation:

From the question given above,

y = 8 × (½)ˣ

When x = –1, y =?

y = 8 × (½)ˣ

y = 8 × (½)¯¹

y = 8 × 2

y = 16

When x = 1, y =?

y = 8 × (½)ˣ

y = 8 × (½)¹

y = 8 × ½

y = 4

When x = 2, y =?

y = 8 × (½)ˣ

y = 8 × (½)²

y = 8 × ¼

y = 2

When x = 3, y =?

y = 8 × (½)ˣ

y = 8 × (½)³

y = 8 × ⅛

y = 1

SUMMARY:

X >>>>> Y

–1 >>>> 16

0 >>>>> 8

1 >>>>> 4

2 >>>>> 2

3 >>>>> 1

4 0
2 years ago
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