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olasank [31]
3 years ago
14

Tan x = sin x / cos x , therefore tan (90-A) = ? . (All angle measurements are in degrees)

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
5 0

Answer:

d. 1/tanA

Step-by-step explanation:

In order to answer, you have to replace x=90-A in the trigonometric identity to express the tangent in function of sine and cosine.

tan(90-A)=\frac{sin(90-A)}{cos(90-A)}

Now you have to apply the following trigonometric identities:

Sin(α-β)=Sin(α)Cos(β)-Cos(α)Sin(β)

Cos(α-β)=Cos(α)Cos(β)+Sin(α)Sin(β)

In this case, α=90 and β=A

Therefore:

\frac{Sin(90)Cos(A)-Cos(90)Sin(A)}{Cos(90)Cos(A)+Sin(90)Sin(A)}

But Sin(90)=1 and Cos(90)=0

\frac{Cos(A)}{Sin(A)} = \frac{1}{tan(A)}

Anna11 [10]3 years ago
3 0

Answer:

Option D. \frac{1}{tanA}

Step-by-step explanation:

tan ( 90-A ) = \frac{sin(90-A)}{cos(90-A)}

since  sin (90-A) = cos A

and cos (90-A) = sin A

So  \frac{sin(90-A)}{cos(90-A)}=\frac{CosA}{SinA}=cot A=\frac{1}{tanA}

Option D. \frac{1}{tanA} is the correct answer.

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8 0
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Help please! thanks! <br> Find the length of AB<br> A. 2.89<br> B. 33.13<br> C. 378.63<br> D. 377.19
Naddik [55]
<h3>Answer:  29 miles (approximate)</h3>

======================================================

Explanation:

Segment AB is already given to be 19 miles long.

I'm assuming your teacher meant to ask about side BC, which is side 'a' since it's opposite angle A.

Use the law of cosines to find the missing side

a^2 = b^2 + c^2 - 2*b*c*cos(A)

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8 0
3 years ago
A store receives shipments of peaches and wants to sort them by weight. Drag each shipment to match the ratio of peaches to poun
Andrej [43]

Answer:


Step-by-step explanation:

Given that a store receives shipments of peaches.  They want to sort them by weight.

The sorting pattern is as follows:

Peaches : Pound = 2:1 or 3.25:1 or 1:3.25

Given are i) 26 peaches to 13 lbs = 26:13=2:1 Hence goes to the first box

ii) 6 peaches to 19.5 lbs =6:19,5 = 1:3,25 lb. Hence goes to II box

iii) 13 peaches to 4 lbs: =13:4=3.25:1   Hence goes to II box

iv) 39 peaches to 12 lbs: =39:12=3.25:1   Hence goes to II box

v) 15 peaches to 7.5 lbs: =15:7.5=2:1   Hence goes to I box

i    - I box

ii   -  II box

iii   - II box

iv) -   II box

v) - I box

8 0
3 years ago
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