Answer:

Step-by-step explanation:
Put <em>n = 10</em> to the equation 

1.30 :)
All you have to do is see if the number on your left is greater than 5 or not if it’s is round up 1 if not it stays the same !
Hope this helped !!!
Answer with Step-by-step explanation:
We are given that a function f(x) is continuous on (
).
1.f'(-1)=0 and f''(-1)=-7
We have to find information about f.
When f'(-1)=0 and f''(-1)=-7 < 0
Then, function is maximum at x=-1.
Therefore, at x=-1, f has local maximum.
Answer:a)at x=-1 ,f has local maximum.
2.) if f'(4)=0 and f''(4)=0
We know that when f''(x)=0 then test fails then the function has not maximum or minimum.
Therefore, at x=4 , f has not a maximum or minimum.
Answer:c) at x=4, f has not a maximum or minimum.
Answer:
5/8
Step-by-step explanation:
The rule is to put them in order