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3 years ago

6. Solve the equation. Show your work. Check your answer. 3x – 7 = 5x + 19

Mathematics

1 answer:

Firdavs [7]3 years ago

3 0

-19 - 7 = 5x - 3x

-26 = 2x

2x= -26

x= -26/2

x= -13

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Luca cut 5 shelves of equal length using 1/2 of a yard of wood. How long was each shelf?

WITCHER [35]

Each shelf was 1/10 of a yard long.

<h3>What are Arithmetic operations?</h3>

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Given that Luca cut 5 shelves of equal length using 1/2 of a yard of wood

There were 5 shelves.

1/2 divided by 5

⇒ (1/2)/5

⇒ (1/2)/(5/1)

⇒ (1/2)(1/5)

⇒ 1/10

Hence, each shelf was 1/10 of a yard long.

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brainly.com/question/10354322

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2 years ago

while jeff was replacing the obstruction of light on a cell tower, he accidentally dropped his cell phone. If he was 150 ft up a

dexar [7]

Answer:

3.19 seconds

Step-by-step explanation:

Given:

Phone gets dropped from a Height = 150 ft

To find:

Time taken for the phone to reach the ground = ?

Solution:

First of all, let us learn about the formula of distance in terms of Initial speed u; Time t and Acceleration a:

$s=ut+\dfrac{1}{2}at^2$

Here the phone is dropped from a height so a = g m/ $s^2$ i.e. acceleration due to gravity.

g = 9.8 m/ $s^2$

s = 150 ft

Initial velocity, u = 0

Putting all the values in the formula:

$150=0 t+\dfrac{1}{2}gt^2\\\Rightarrow 50=\dfrac{1}{2}\times 9.8 \times t^2\\\Rightarrow t^2=\dfrac{50}{4.9 }\\\Rightarrow t^2=10.20\\\Rightarrow t = 3.19\ sec$

So, the time taken is 3.19 seconds.

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3 years ago

Find the difference ( 9/4x+6) − (− 5/4x−24)=

Amiraneli [1.4K]

Answer:

$=\frac{7}{2}x+30$

Step-by-step explanation:

So we have the equation:

$(\frac{9}{4}x+6)-(-\frac{5}{4}x-24})$

First, distribute the negative on the right:

$=(\frac{9}{4}x+6)+(\frac{5}{4}x+24})$

Combine like terms:

$=(\frac{9}{4}x+\frac{5}{4}x})+(6+24)$

Add:

$=\frac{14}{4}x+30$

We can reduce our fraction by dividing both layers by 2. Thus:

$=\frac{7}{2}x+30$

So this would be our answer :)

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3 years ago

Which number is equivalent to 49 ÷9

Varvara68 [4.7K]

Answer:

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3 years ago

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