Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is
Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,
Putting the given values, we get
Therefore, the area of 4 walls of the room is 54 sq. metres.
I believe it would be 8 km in five miles. I hope this helped ^^
Answer:
cos theta = 4/5
Step-by-step explanation:
Since this is a right triangle
Cos theta = opp side/ hypotenuse
Cos theta = 8/10
cos theta = 4/5
Hello and Good Morning/Afternoon:
<u>Let's take this problem step-by-step:</u>
<u>First off, let's write the line in point-slope form:</u>
- (x₀, y₀) any random point on the line
- 'm' is the value of the slope
<u>Let's calculate the slope:</u>
- (x₁, y₁): any random point on the line ⇒ (-2, -6)
- (x₂,y₂): any random point on the line that is not (x₁, y₁) ⇒ (2, -3)
<u>Now that we found the slope, let's put it into the point-slope form</u>
⇒ we need (x₀, y₀) ⇒ let's use (2,-3)
<u>The equation, however, could also be put into 'slope-intercept form'</u>
⇒ gotten by isolating the 'y' variable to the left
<u>Answer:</u> or 
*<em>Either equations work, put the one that you are the most familiar with</em>
Hope that helps!
#LearnwithBrainly
