Given the Arithmetic sequence A1,A2,A3,A4 45, 51, 57, 63 What is the value of A34?

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

8 0

Answer:

Value of A(34) = 219

Step-by-step explanation:

A1, A2,A3,A4,45,51,57,63 are in Arithmetic sequence

Common difference in this Arithmetic sequence = 63 - 57 = 06

so, A4 = 45 - 6 = 39

A3 = 39 - 6 = 33

A2 = 33 - 6 = 27

A1 = 27 - 6 = 21

First term of Arithmetic sequence = 21

Common difference = 06

Using general term of Arithmetic sequence,

A(n) = First term + (n - 1) common difference

A(34) = 21 + (34 - 1) 6

A(34) = 21 + 33 × 6

A(34) = 21 + 198

A(34) = 219

Value of A(34) = 219

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