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rodikova [14]
3 years ago
9

Given the Arithmetic sequence A1,A2,A3,A4 45, 51, 57, 63 What is the value of A34?

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
8 0

Answer:

Value of A(34) = 219

Step-by-step explanation:

A1, A2,A3,A4,45,51,57,63 are in Arithmetic sequence

Common difference in this Arithmetic sequence = 63 - 57 = 06

so, A4 = 45 - 6 = 39

     A3 = 39 - 6 = 33

     A2 = 33 - 6 = 27

     A1 = 27 - 6 = 21

First term of Arithmetic sequence  = 21

Common difference = 06

Using general term of Arithmetic sequence,

A(n) =  First term + (n - 1) common difference

A(34) = 21 + (34 - 1) 6

A(34) = 21 + 33 × 6

A(34) = 21 + 198

A(34) = 219

Value of A(34) = 219

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8 0
3 years ago
Can someone please help me with question 1, I will mark you as a brainest and I'll thank you
Leya [2.2K]
I believe it is 86.4
8 0
3 years ago
ANSWE PLEASEEEEEEEEEEEEEEE
Natalka [10]

Answer:

your answer is gonna be A!! <3

Step-by-step explanation:

1 Subtract 33 from both sides.

y-3=-2x

y−3=−2x

2 Divide both sides by -2−2.

-\frac{y-3}{2}=x

−

2

y−3

=x

3 Switch sides.

x=-\frac{y-3}{2}

x=−

2

y−3

5 0
2 years ago
does anyone understand this or can anyone explain what i need to do please ?? there’s no instructions
Contact [7]

Answer:

nah man... good luck tho

3 0
3 years ago
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