4s+7a=861
s+a=168
This can be solved using either elimination or substitution. I am going to use substitution.
Solve s+a=168 for s
s=168-a
Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861
Solve for a
672+3a=861
3a=189
a=63
Substitute 63 for a in s=168-a
s=168-63=105
So, s=105 student tickets and a=63 adult tickets
Answer:
(x+3)^2+(y+2)^2=80
Step-by-step explanation:
Answer:
37
Step-by-step explanation:
first you need to add 1 plus 4 which is 5. then square it so it becomes 25. Then using order of operations do 6 times 2 which is 12 and add it to 25 to get 37.
Answer:
easy so for the copy and go for the second box it would be $0.12 Step-by-step explanation:
The standard quantity of metal per ring is 0.57 kilograms.
Step-by-step explanation:
Each ring requires 0.52 kilograms of a special metal.
The allowance for waste is 0.03 kilograms per ring, while the allowance for rejects is 0.02 kilograms per ring.
So, the standard quantity of metal per ring = 0.52 kg of metal required + 0.03 kg of allowance for waste + 0.02 kg of allowance for rejects)
=
kilograms.
Hence, the standard quantity of metal per ring is 0.57 kilograms.