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Vinvika [58]
4 years ago
11

Suppose the probability of an event occurring is P(A), and the probability of the event not occurring is P(A’). If P(A)= x and P

(A’)= y, which of the following equations must be true
Mathematics
1 answer:
larisa86 [58]4 years ago
6 0

The correct answer is A) t = 1-s.

The probability of the complement of an event is the probability of the event subtracted from 1; in other words

P(A') = 1 - P(A)

Since P(A') = t and P(A) = s,  

t = 1-s

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Two sides of a triangle measure 25 cm and 35 cm. What is the meadure of the third side?
SpyIntel [72]

Answer:

43cm

Step-by-step explanation:

use the pythagorean theorem:

a² + b² = c²

25² + 35² = c²

625 + 1225 = c²

1850 = c²

√1850 = c

43 cm = c

your a, b and c values depend on where the values are on the triangle.

4 0
4 years ago
What is the unit rate of 88 students for 4 classes
Nat2105 [25]
So, We Have A Rate That We Need To Simplify. We Have:
88 students for every 4 classes
So, We Need To Simplify This Rate. In Order To Do This, We Need To Change Is To A Fraction. It Is:
88 students
---------------
  4 classes

Now, We Have To Simplify. We Can Do That By Remembering How To Simplify Fractions.

So,
88 ÷ 2 =  44   ÷ 2  =   22 students
---            ---               ---------------
 4  ÷ 2 =   2    ÷ 2  =           1

So, The Unit Rate For 88 Students For 4 Classes Is:
22 Students For One Class

5 0
4 years ago
Which section of the function is decreasing? (4 points)
vredina [299]

Answer:

Step-by-step explanation:

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8 0
3 years ago
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If 3 pipes can fill the tank completely in 2 hour then when will 1 pipe fill the tank​
Montano1993 [528]

Answer:

6 hours

Step-by-step explanation:

8 0
3 years ago
The incline of a roller coaster is 2 times as long as its elevation, and the horizontal length of the roller coaster is 11 m mor
Gelneren [198K]
Let 
x-------> t<span>he horizontal length of the roller coaster
y------> </span>the elevation of the roller coaster
c------> t<span>he incline of a roller coaster
</span>
we know that
applying the Pythagoras theorem
c²=x²+y²-----> equation 1
c=2y-----> equation 2
x=11+y----> equation 3

substitute equation 2 and equation 3 in equation 1
[2y]²=(11+y)²+y²
4y²=11²+22y+y²+y²
2y²-22y-121=0

using a graph tool-----> to resolve the second order equation
see the attached figure

the solution is 
y=15.026 m

c=2*y-----> c=2*15.026----> c=30.052 m

the answer is
30.05 m


7 0
3 years ago
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