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Vinvika [58]
3 years ago
11

Suppose the probability of an event occurring is P(A), and the probability of the event not occurring is P(A’). If P(A)= x and P

(A’)= y, which of the following equations must be true
Mathematics
1 answer:
larisa86 [58]3 years ago
6 0

The correct answer is A) t = 1-s.

The probability of the complement of an event is the probability of the event subtracted from 1; in other words

P(A') = 1 - P(A)

Since P(A') = t and P(A) = s,  

t = 1-s

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The answer would be -11
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3 years ago
Find the length of BC.
Umnica [9.8K]

Answer:

BC = 8

Step-by-step explanation:

AB + BC = AC

4x + 8 + 3x - 4 = 32

7x + 4 = 32

7x = 32 - 4

7x = 28

x = 28/7

x = 4

BC = 3x - 4 = 3*4 - 4 = 12 - 4 = 8

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2 years ago
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Answer:

1) Less than

2) greater than

Step-by-step explanation:

Equation of the first line:

(y+7)/(-13+7) = x/-1

(y+7))/-6 = -x

y+7 = 6x

y= 6x - 7

Equation of the second line:

A (4/3,0) ; B (0,8)

y/8 = (x-4/3)/-4/3

y/8 = (x-4/3) * -3/4

y/8 = -3/4x + 1

y = -6x + 8

8 0
3 years ago
HELPPPPP. I’ve spent like 20 minutes on this already pleaseeee
alexandr402 [8]

Answer:

x=126

x-30=96

Step-by-step explanation:

(x-30) +(x-30) + (x-30) + x + x =540

5x-90=540

5x=630

x=126

5 0
3 years ago
Question 1 (1 point)
kykrilka [37]

Answer:

The description for the problem is listed throughout the section below on explanations.

Step-by-step explanation:

The given values are:

The amount of bank loan = $22,000

Interest rate = 7.99%

Pays monthly = $700

So, the principal amount decreases by 700 per month.

Now,

The principal amount at the end of the m^{th} month = (22000 - 700 m)

Then,

The interest paid at the end of 1 year:

⇒ (22000)0.0799+(22000-700)0.0799+...+(22000-700(11))0.0799

On simplifying the above equation, we get

⇒ 0.0799[12(22000)-\frac{11\times 12}{2}\times 700]

⇒ 0.0799[264000-11\times 6\times 700]

⇒ 0.0799[264000-46200]

⇒ $17402.22

Therefore interest could be measured correctly at the end of each year, likewise.

⇒ (2200-700m)R+(22000-700(m+1))R+...+(22000-700(m+11))R

⇒ R[12\times 22000-700[12m+\frac{11\times 12}{2}]]

⇒ R[264000-700[12m+\frac{11\times 12}{2}]]

⇒ R[263300(12m+66)]

R : interest rate

7 0
4 years ago
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