Grace made 14 free throws a minute
() is a subset of every set
If the number is a multiple of 8, it is divisible by 8.
The multiples of 8 are: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88... etc.
If a number is very big, let's say 176, see if you can deduct 80 from it. For this, 176 can be deducted by 80 twice, which will give you a remainder of 16 (I.e. 176 - 80 - 80 = 16". If this remainder (i.e. 16) is divisible by 8, 176 is divisible by 8.
For even larger numbers, try deducting 800, or even 8000.
Let's say you're trying to see if 2464 is divisible by 8. In this case, 2464 can be deducted by 800 thrice (I.e. 2464 - 800 - 800 - 800 = 64), and 64 is its remainder. Since 64 is divisible by 8, 2464 is divisible by 8.
Hope this helps! :)
Answer:
Below.
Step-by-step explanation:
f(x) = a(x - j)^2 + k is the standard vertex form where (j, k) is the vertex,
f(x) = (x + 3)^2 + 4
Comparing this to the standard form we see that:
vertex = (-3, 4)
Answer:
Step-by-step explanation:
Perimeter
Let the smaller figure have n sides
Then the perimeter of the smaller figure = n * s
The perimeter of the larger figure = n*s1
The ratio would be n*s / n*s1 = 6/11 because the ns cancel out.
Area
The area is much harder.
If the figure is a regular polygon (all sides equal and convex) then both the sides and the apothem are both in a 6 to 11 ratio.
The formula for the area of a regular polygon is
Area = (n * s * a)/2
The apothem is the length of the line from the center of polygon to the middle of one of the sides.
S_L = the length of the larger side
S_s = the lenght of the smaller side
A_L = the length of the larger apothem
A_s = the length of the smaller apothem
Area_s = (n * S_L * A_L)/2
Area_L = (n * S_s * A_s)/2
The 2 s will cancel out
The ns will cancel out
S_s / S_L = 6/11
A_s / A_L = 6/11
Area_s / Area_L = (6 / ll ) ^2
Area_ s / Area_L = 36/121