Answer:
BC = 8
Step-by-step explanation:
AB + BC = AC
4x + 8 + 3x - 4 = 32
7x + 4 = 32
7x = 32 - 4
7x = 28
x = 28/7
x = 4
BC = 3x - 4 = 3*4 - 4 = 12 - 4 = 8
Answer:
1) Less than
2) greater than
Step-by-step explanation:
Equation of the first line:
(y+7)/(-13+7) = x/-1
(y+7))/-6 = -x
y+7 = 6x
y= 6x - 7
Equation of the second line:
A (4/3,0) ; B (0,8)
y/8 = (x-4/3)/-4/3
y/8 = (x-4/3) * -3/4
y/8 = -3/4x + 1
y = -6x + 8
Answer:
x=126
x-30=96
Step-by-step explanation:
(x-30) +(x-30) + (x-30) + x + x =540
5x-90=540
5x=630
x=126
Answer:
The description for the problem is listed throughout the section below on explanations.
Step-by-step explanation:
The given values are:
The amount of bank loan = $22,000
Interest rate = 7.99%
Pays monthly = $700
So, the principal amount decreases by 700 per month.
Now,
The principal amount at the end of the
month = (22000 - 700 m)
Then,
The interest paid at the end of 1 year:
⇒ 
On simplifying the above equation, we get
⇒ ![0.0799[12(22000)-\frac{11\times 12}{2}\times 700]](https://tex.z-dn.net/?f=0.0799%5B12%2822000%29-%5Cfrac%7B11%5Ctimes%2012%7D%7B2%7D%5Ctimes%20700%5D)
⇒ ![0.0799[264000-11\times 6\times 700]](https://tex.z-dn.net/?f=0.0799%5B264000-11%5Ctimes%206%5Ctimes%20700%5D)
⇒ ![0.0799[264000-46200]](https://tex.z-dn.net/?f=0.0799%5B264000-46200%5D)
⇒ $
Therefore interest could be measured correctly at the end of each year, likewise.
⇒ 
⇒ ![R[12\times 22000-700[12m+\frac{11\times 12}{2}]]](https://tex.z-dn.net/?f=R%5B12%5Ctimes%2022000-700%5B12m%2B%5Cfrac%7B11%5Ctimes%2012%7D%7B2%7D%5D%5D)
⇒ ![R[264000-700[12m+\frac{11\times 12}{2}]]](https://tex.z-dn.net/?f=R%5B264000-700%5B12m%2B%5Cfrac%7B11%5Ctimes%2012%7D%7B2%7D%5D%5D)
⇒ ![R[263300(12m+66)]](https://tex.z-dn.net/?f=R%5B263300%2812m%2B66%29%5D)
R : interest rate