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3 years ago

How did de broglie conclude that electrons have a wave nature

Physics

1 answer:

eimsori [14]3 years ago

5 0

<h2>Answer: By the double slit experiment applied to electrons</h2>

The French physicist Louis De Broglie proposed the existence of matter waves, that is to say that <u>all matter has a wave associated with it.</u>

On the other hand, Heisenberg enunciated the uncertainty principle, which postulates that the fact that <u>each particle has a wave associated with i</u>t, imposes restrictions on the ability to determine its position and speed at the same time.

These postulations were tested with the double slit experiment (formerly applied to photons) applied to electrons, and the result was: electrons (as well as the other particles different from the photons) are able to behave as waves.

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A pitcher releases a fastball that moves toward home plate.

Vsevolod [243]

The two additional forces that act on the ball as it travels between the pitcher and the home plate are air resistance and gravity.

<h3>What are the forces that affect object in motion;</h3>

Air resistance: this is the force that oppose the motion of an object in air due to frictional force
Gravity: this is the force due to weight of the object and acts downwards.

The two additional forces that act on the ball as it travels between the pitcher and the home plate include:

Air resistance and
Gravitational force

<h3>How the forces affect the motion of the ball</h3>

Air resistance oppose the motion of the ball as it travels in air.
Gravity is the force due to weight of the ball and acts downwards.

Learn more about forces on object in motion here: brainly.com/question/10454047

5 0

3 years ago

If the normal force exerted by the track on the car when it is at the top of the track (point B) is 6.00 N , what is the normal

Eddi Din [679]

Answer:

So, the force, F is the agent which provides the basic property of motion or rest to the body.While, the car is more obviously to have a mass, m and that the angle withe road or surface is also given which is normal to the road(i.e angle =90 degree). Then we say that lets say that the car is moving with the constant velocity of 20 m/sec and its kept unchanged by the car. So, we have the mass, m as 1 kg for the car and the value of the gravity we have the g=9.8 m/sec.

Now,

We have F=ma,

and a=v/t,

so we can have another equation for it as,

Now, providing the required data to, it; ∴t =2 sec,

F=(1)×(20/2),

<u>F=10 N.</u>

So, the car would be acting the force,F of about 10 N while the car is present on the lower region of the track.

4 0

3 years ago

What is your weight on Venus, assuming that the acceleration due to gravity on Venus is 8.875 m/s^2 and your mass is 50 kg.

Volgvan

Answer:

Weight on Venus = 443.75 N

Explanation:

Weight of a body is the product of mass and acceleration due to gravity.

So we have

Weight = Mass x Acceleration due to gravity

W = mg

Mass, m = 50 kg

Acceleration due to gravity, g = 8.875 m/s²

W = 50 x 8.875 = 443.75 N

Weight on Venus = 443.75 N

3 0

3 years ago

Read 2 more answers

A 7.0 mm -diameter copper ball is charged to 40 nC. What fraction of its electrons have been removed? The density of copper is 8

mylen [45]

Answer:

$f = 2.6 \times 10^{-13}$

Explanation:

Let the mass of copper ball is "m" gram

now the total number of copper atom present in the ball is given as

$N = \frac{m}{29} \times 6.02 \times 10^{23}$

now the total number of electrons in one copper atom is 29

so total number of electrons in given sample of copper ball is

$N_e = m(6.02 \times 10^{29})$

now diameter of the ball is 7.0 mm

density of the ball = $8900 kg/m^3$

now we have

$m = (\frac{4}{3}\pi r^3)(8900)$

$m = (\frac{4}{3}\pi(\frac{0.007}{2})^3)(8900)$

$m = 1.6 gram$

now we have

$N_e = 9.63 \times 10^{23}$

now the charge on the copper ball is 40 nC

so the number of electrons removed

$Q = ne$

$40 \times 10^{-9} = n(1.6 \times 10^{-19}$

$n = 2.5 \times 10^{11}$

so the fraction of number of electrons removed is given as

$f = \frac{n}{N_e}$

$f = \frac{2.5 \times 10^{11}}{9.63 \times 10^{23}}$

$f = 2.6 \times 10^{-13}$

7 0

4 years ago

Help please! Asap!!<br> (I selected some yes/no but I don't know the answer) <br> (Either yes or no)

Yuki888 [10]

Mass - Yes - Yes

Drop height - Yes - Yes

Initial velocity - No - No

Acceleration due to gravity - Yes - Yes

Object size - No - No

Hope this helps!

4 0

4 years ago

Read 2 more answers