Answer:
The angle of launch is 52.49 Degree.
Explanation:
The Range R and Height H of a thrown object is calculated using the formula,
R=V₀² sin(2φ)/g
H=V₀²sin²(φ)/g
From these equations it can be written,
V₀²=R g/ sin(2φ)
V₀²=H g/ sin²(φ)
These values are equal so it can be written by equating these equations,
R g/sin(2φ)=H g/sin²(φ)
tan(φ)= 2H/R
Given H=72.3 m and R=111 m, the angle of launch is,
tan(φ)= 2*72.3/111
φ= 52.49 Degree.
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Answer:
b. Both the gratings will produce the same separation of peaks.
e. The grating with 10 slits will produce better-defined(narrower) peaks.
Answer: 219,344.5 j
Explanation:
from the question we have the following parameters
mass of barge (m) = 5 x 10^4 kg
angle of ropes (θ) = 45 degrees
force by each mule (F1) = 1.10 kN = 1100 N
force by each mule (F2) = 1.10 kN = 1100 N
distance (s) = 141 m
work done by the mules = force x cos θ x distance
since we are calculating the force of both mules we have to both mules before we can use in the equation
force = 1100 + 1100 = 2200 N
work done = 2200 x cos (45) x 141
work done = 219,344.5 j
Answer: [B]: The letter, "<em /> I " ; for current; in units of "Amps" .
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