The electrostatic force between two charges is given by
where
ke is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the charges
In our problem,
Therefore the electrostatic force is
Answer:
80 times 12=960
Explanation:
You have to do the equation for work, the equation is work= force times distance, the force here is 80newtons, the distance is 12meters, so you would do 80 times 12 to get your answer of 960
The easiest way to answer this question is by realizing there are relating the velocities of the two cars. To tackle this problem, you have to understand the picture. Car 1 travels at 35m/s and Car 2 travels at 25m/s. Based on relative velocities, we can understand that Car 1 travels 10m/s faster than Car 2 every second. So we can interpret Car 1's relative velocity to Car 2 as 10m/s. Car 1 needs to travel 10m/s till a point of catching up to Car 2 which is 462m away.
v = 10m/s
d = 462m
v = d/t
(10) = (462)/t
t = 46.2s
So it takes 46.2 seconds for Car 1 to catch up to Car 2, but the question is asking how far does Car 1 travel to catch up. So we have to use Car 1's velocity and not the relative velocity:
v = 35m/s
v = d/t
(35) = d/(46.2)
d = 1617m
Car 1 traveled a total distance of 1617m.
Answer:
12
Explanation:
What is the total kinetic energy of a hoop of radius 1 m and mass 2 kg that rolls at an
angular velocity of 1 rad/s?
Answer:
The corresponding dimensions will be "x = 300 & y = 60".
Explanation:
Available fencing = 600 ft
Fencing,
⇒ 
⇒ 
As we know,
⇒ 
On substituting the given values, we get
...(equation 1)
On differentiating with respect to y, we get
⇒ 
On putting the values of y in equation 1, we get
⇒ 
⇒ 
⇒ 
⇒ 
Dimensions of the rectangular area:
x = 300
y = 60
