There is no congruence between the triangles based on the given information. In general, two sides and an angle not between them are insufficient to specify the triangle completely. In this case, the angles that are congruent are adjacent to non-corresponding sides, so even if SSA correspondence were sufficient to ensure congruence, it would not be sufficient in this case.
The appropriate choice is
... none
Essentially, what we need to do here is prove that BE=EC, BE=CB, and.or CE=BC therefore making it isosceles. With ∠AEC=∠DEB, we know AE=DE, so EC=EB (the points go in order). Therefore, as EC=EB, BEC is isosceles (it has at least 2 equal sides).
Feel free to ask further questions!
Answer:
Step-by-step explanation:
If I'm not mistaken by the question, we have
Multiply through by the LCM of all the denominators to clear the fractions. Since we have only one fraction, we multiply through by its LCM (3)
Putting all terms on the LHS (left hand side) and evaluating,
Y=2x+4
y=2x-4
and the last one is already in standard form
Answer:
i am not sure but according to me ans is d
Step-by-step explanation:
Ax+By=C
Ax=C-By
A=C-By/x
