Simplify the expression. 15y^7-6-y^5 + 3y^4 / 6y^4
1 answer:
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To solve the problem we must know about quadratic equations.
<h2>Quadratic Equation</h2>A quadratic equation is an equation that can be written in the form of
ax²+bx+c.
Where a is the leading coefficient, and
c is the constant.
The breadth of the rectangle is 200 ft, while the length is 210 ft.
<h2>Explanation</h2>Given to us
- Area of the parking lot = 42,000 ft²
- Perimeter of the parking lot = 820 ft
Area of the parking lot = Area of the rectangle
42,000 ft² = Length x Breadth
Solving for L,
Perimeter of the parking lot = Perimeter of the rectangle
820 ft. = 2(Length + Breadth)
820 ft. = 2(L+ B)
Substituting the value of L,
Solving the quadratic Expression,
Equation the factors against zero,
B-210=0
B = 210
B-200=0
B = 200
Hence, the breadth of the rectangle is 200ft, while the length is 210 ft.
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