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lidiya [134]
3 years ago
5

Change this radical to an algebraic expression with fractional exponents.

Mathematics
1 answer:
vekshin13 years ago
7 0

Rational exponents

a^\frac{m}{n}

work like this: the numerator is the actual exponent of the base, while the denominator is the index of the root.

In other words, we have

a^\frac{m}{n}=\sqrt[n]{a^m}

So, in you case, we have

\sqrt[5]{x^3}=x^\frac{3}{5}

Assuming that the question contanis a typo. If you actually mean 5\sqrt{x^3},

then you can write it as 5x^\frac{1}{3}

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What are the critical points for the inequality 2x+5/x-2≥x-1/x-2?
Pachacha [2.7K]
1) When the denominator equals zero that is a critical point

=> x - 2 = 0 => x = 2.

So x = 2 is a critical point

2) Simplify the numerator to find an expresion of the king p(x) ≥ 0 or p(x) ≤ 0. Where p(x) equals zero you have other(s) critical point(s)

Multiply both terms:

[2x + 5] / [ x - 2] = [x - 1] / [x - 2]

for x ≠ 2 => 2x + 5 = x - 1

=> 2x - x = - 1 - 5

=> x = - 6

Then, the two critical points are x = 2 and x = - 6.

Answer: option B.
3 0
3 years ago
Read 2 more answers
Denise bought 116 ounces of beans for a bean dip. She bought both 15-ounce cans and 28-ounce cans, and the total number of cans
Valentin [98]
15x + 28y = 116
x + y = 6

that would be ur system of equations

7 0
3 years ago
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H>
arsen [322]

Answer:

C

Step-by-step explanation:

3*-4

3 0
3 years ago
-2x > -10 solve for x
Korvikt [17]

Answer:

x<5

Step-by-step explanation:

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4 0
3 years ago
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Help solve 88 please
Fofino [41]

Answer:

The equation of the line is y = -2x + 7

Step-by-step explanation:

* Lets study how to make an equation of the line from two point

- If the line passes through points (x1 , y1) and (x2 , y2)

- The form of the equation is y = mx + c, where m is the slope of the

 line and c is the y-intercept

- The rule of the slope is m = (y2 - y1)/(x2 - x1)

- The y-intercept means the line intersect the y-axis at point (0 ,c)

* Now lets solve the problem

∵ The line passes through points (-3 , 13) and (4 , -1)

- Let (-3 , 13) is (x1 , y1) and (4 , -1) is (x2 , y2)

∵ m = (y2 - y1)/(x2 - x1)

∴ m = (-1 - 13)/(4 - -3)

∴ m = (-14)/7 = -2

- Lets write the form of the equation

∵ y = mx + c ⇒ substitute the value of m

∴ y = -2x + c

- To find the value of c use one of the two points to substitute the

  values of x and y in the equation

∵ The line passes through (4 , -1)

∴ -1 = -2(4) + c

∴ -1 = -8 + c ⇒ add 8 to both sides

∴ -1 + 8 = -8 + 8 + c

∴ 7 = c

∴ y = -2x + 7

* The equation of the line is y = -2x + 7

4 0
3 years ago
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