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Iteru [2.4K]
2 years ago
8

Does anyone know the answer to these 2 questions they both have to be rounded to the nearest tenth and you’re only solving for x

Mathematics
1 answer:
Sophie [7]2 years ago
6 0

Answer:

1) 24.2 = x    2) 27.8 = x

Step-by-step explanation:

1) Find the cos 21 degrees

cos 21 = x/26     Simplify

0.93 = x/26        Multiply 0.93 and 26

24.2 = x

2) Find the sin 33 degrees

sin 33 = 15/x       Simplify

0.54 = 15/x          Divide both sides by 0.54

27.8 = x

If these answers are correct, please make me Brainliest!

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Solve exponents please help just this one u get 10 points
STALIN [3.7K]
I think it's equal to 1 because every expression with the exponent of zero is equal to 1, idk for sure though
8 0
2 years ago
Find the quadratic function y=​f(x) whose graph has a vertex ​(−3​,4​) and passes through the point ​(−7​,0). Write the function
olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola.  The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.  

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front.  So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex:  x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

a=-\frac{1}{4}

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

y=-\frac{1}{4}(x+3)^2+4

Now we will FOIL out what's inside the parenthesis to get

y=-\frac{1}{4}(x^2+6x+9)+4

Simplify by distributing the -1/4 into the parenthesis:

y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4

Combine like terms to get

y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}

And there you go!

5 0
2 years ago
{(-1, 4), (-1,9), (-1; 15), (-1,0)}<br> D =<br> R=<br> Function?<br><br> Please help
tatiyna
D= {-1}
R= {4,9,15,0}
Function? No, the relation is not a function.
4 0
2 years ago
In isosceles pqr with base , pq = 2x + 3, and pr = 9x - 11. what is the value of x?
Anon25 [30]
First, draw and label a rough sketch of an isosceles triangle. Now put in the values of pq=2x+3 and pr=9x-11 

You know that the triangle is isosceles, therefore, the sides pq and pr are identical.  

Now, make the equations equal to each other to find the value of x. 

2x+3=9x-11 
3+11=9x-2x 
14=7x 
14/7=x 
2=x 

Therefore the value of x=2. 

Hope I helped :) 
8 0
2 years ago
A group of students volunteered to finish a task in 25 days .1 Q of students did not come n the work could b completed in 35 day
SpyIntel [72]

Answer:

p=7Q/2

Step-by-step explanation:

Original number of students:

p students to do 1 job in 25 days.

Let r= the rate for 1 student.

pr*25=1

pr*25=1 is the work rate equation for p students.

Lesser number of students:

p-Q students came to do the job and time required was 35 days.

(P-Q)*r*35=1.

The unknowns are p, Q and r

Equate the original number of students and the lesser number of students

pr*25=(P-Q)*r*35

25rp=35rp - 35Qr

Collect like terms

25rp-35rp = -35Qr

Divide both sides by -5

-5rp+7rp=- 7rp

It can be re written as

7rp-5rp=-7Qr

2rp=7Qr

Make p the subject of the formula

p=7Qr/2r

p=7Q/2

p=7Q/2 is the original number of students

-10rp = -35Qr

The system of these two equations can be solved for p. See the THREE unknown

variables, p, r, and Q. You might assume that either r or Q would be a constant.

5 0
2 years ago
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