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SashulF [63]
3 years ago
10

Melinda rode her bilke 54/100 mile to the library. Then she rode 4/10 mile to the store. How far did melida ride her bike in all

?
Mathematics
1 answer:
adell [148]3 years ago
7 0
94/100 mile in total
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A college has a student to teacher ratio of 35 to 2. If there are 180 teachers at the college, how many students attend the coll
Ray Of Light [21]

number of student attend the college are 3150

Step-by-step explanation:

the student teacher ratio is 35:2

let, there are 2x teachers

according to the problem,

2x = 180

or, x = 180/2

= 90

so number of students = 35 X 90 = 3150

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3 years ago
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finlep [7]

Answer:

Step-by-step explanation:

A. 221 x 5 = 1,105

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3 years ago
Let O be an angle in quadrant III such that cos 0 = -2/5 Find the exact values of csco and tan 0.​
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well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}

\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}

4 0
2 years ago
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stich3 [128]

Answer:

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Step-by-step explanation:

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2 years ago
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