Answer:
look up math way put in your decimal and ask it to convert into a fraction
Step-by-step explanation:
Answer:
Step-by-step explanation:
yes.
Assume you have the function:
![f(x)=\frac{1}{\sqrt{x} }](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B%5Csqrt%7Bx%7D%20%7D)
Then in order to rationalize the denominator, you'd multiply the whole function by 1:
![f(x)=\frac{1}{\sqrt{x} } *\frac{\sqrt{x} }{\sqrt{x} } =\frac{\sqrt{x} }{x\\}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B%5Csqrt%7Bx%7D%20%7D%20%2A%5Cfrac%7B%5Csqrt%7Bx%7D%20%7D%7B%5Csqrt%7Bx%7D%20%7D%20%3D%5Cfrac%7B%5Csqrt%7Bx%7D%20%7D%7Bx%5C%5C%7D)
Answer:
It’s not linear so it can’t be solved
Step-by-step explanation:
Given:
![\frac{64}{81}=d^2](https://tex.z-dn.net/?f=%20%5Cfrac%7B64%7D%7B81%7D%3Dd%5E2%20)
All of the items are perfect squares, so we can take the square root of both sides easily:
![\sqrt{\frac{64}{81}}=\sqrt{d^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B64%7D%7B81%7D%7D%3D%5Csqrt%7Bd%5E2%7D)
Simplify.
![\frac{8}{9}=d](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%7D%7B9%7D%3Dd)
OR
![-\frac{8}{9}=d](https://tex.z-dn.net/?f=%20-%5Cfrac%7B8%7D%7B9%7D%3Dd)