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valina [46]
3 years ago
11

The domain of y = VX-5 - 1 is

Mathematics
1 answer:
AnnZ [28]3 years ago
4 0

Answer:

All Real Numbers

Step-by-step explanation:

Assuming that V is just a constant, you can re-write the equation as:

y = Vx-6.  

This is a linear equation.  Linear equations have a domain and range that both are "all real numbers".

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A ballplayer catches a ball 3.4s after throwing it vertically upward. with what speed did he throw it, and what height did it re
Daniel [21]

From the equation of motion, we know,

s=ut+\frac{1}{2}at^{2}

Where s= displacement

u= initial velocity

a= gravitational force

t= time

Displacement is 0 since the ball comes back to the same point from where it was thrown.  

A = -9.8m/s^{2} since the ball is thrown upwards.

Plug the known values into the equation.

=> 0=u\left ( 3.4 \right )+\frac{1}{2}\left ( -9.81 \right )(3.4^{2})

Solving for u gives :

u= 16.67 m/ sec ....... equation (1)

At maximum height, final velocity i.e v is 0

Time take to reach the top = \frac{3.4}{2} = 1.7 sec

v^{2}=u^{2}+2as

=> 0=(16.67)^{2}+2(-9.81)(s)

Solving for s we get

s= 14.16 m


4 0
3 years ago
Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution,
Gnom [1K]

Answer:

x1=-4/5, x2=18/5 and x3=7/5

Step-by-step explanation:

\left[\begin{array}{ccc|c}1&0&-3&-5\\3&1&2&4\\2&2&1&7\end{array}\right]

you can do linear combination between the rows:

2nd row=R2-3R1 and 3th row=R3-2R1

\left[\begin{array}{ccc|c}1&0&-3&-5\\0&1&11&19\\0&2&7&17\end{array}\right]

3th row=(3R2-R3)/15

\left[\begin{array}{ccc|c}1&0&-3&-5\\0&1&11&19\\0&0&1&\frac{7}{5} \end{array}\right]

1st row=R1+3R3 and R2-11R3

\left[\begin{array}{ccc|c}1&0&0&-4/5 \\0&1&0&18/5 \\0&0&1&7/5\end{array}\right]

x1=-4/5, x2=18/5 and x3=7/5

6 0
3 years ago
Please help. I will give brainliest to correct answer.
Stells [14]

Answer:

The area of a square with side length of 2 inches is 4 square inches.

The area of a circle with radius 1.2 inches is:

\pi \times (1.2) ^{2}  \\  = 3.14 \times 1.44 \\  = 4.5216 \: square \: inches

That is approximately 4.5 square inches.

Hence, the area of the square (4) is less than {<} that of the circle (4.5)!

3 0
2 years ago
Does anyone know the answer to this problem?
nataly862011 [7]

Answer:

15

Step-by-step explanation:

3^2 + sqrt4 + 4

3^2 = 9

sqrt4 = 2

(9)+(2)+(4)=15

therefore, the answer is 15

4 0
3 years ago
The photo shows the San Andreas fault zone. This is a
Tju [1.3M]

Answer:

i think u should attach the photo...

i think the answer is rift valleys

6 0
3 years ago
Read 2 more answers
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