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GREYUIT [131]
3 years ago
10

For the standard normal probability distribution, the area to the left of the mean is

Mathematics
1 answer:
Alborosie3 years ago
6 0
Any normal distribution is symmetric about its mean, so

\mathbb P(X

where \mu is the mean for the distribution.
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Solve this system of linear equations. Separate
alex41 [277]

Answer:

y = 7 and x =3

Step-by-step explanation:

use elimination method

so we gonna eliminate y first

9x = 1 - 4y

-7x = -7 + 4y

7| 9x = 1 - 4y

9| -7x = -7 + 4y

63x = 7 - 28y

-63x = -63 + 36y

add eqtn 1 to eqtn2

you will get

0 = -56 + 8y

56 = -56 + 56 + 8y

56 = 8y

56÷8 = 8y÷ 8

7 = y

also eliminate x as we have done wth y

4| 9x = 1 - 4y

4| -7x = -7 + 4y

36x = 4 - 16y

-28x = -28 + 16y

add the two equations

u will get

8x = -24 + 0

8x = -24

8x÷8 = 24÷ 8

x = 3

5 0
3 years ago
The ratio of sixth graders to seventh graders at the school dance is 2 to 3.
Inessa [10]

Answer:

18

Step-by-step explanation:

2:3 x 9

18:27

18 + 27 = 45

6 0
3 years ago
A rectangular solar panel has a length of 11 inches shorter than 4 times it’s width if the perimeter of the panel is 218 inches
larisa [96]
Rip king von‼️ to send respect mark me brainiest
7 0
3 years ago
Kami is in charge of creating a five-digit code to lock and unlock a secure chamber. She can use any digit from 0 through 9, and
Pavlova-9 [17]

Using the Fundamental Counting Theorem, it is found that Kami could create 40,000 codes that start with an even number.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

In this problem:

  • The first digit has to be even, that is, 2, 4, 6 or 8, hence n_1 = 4.
  • For the remaining digits there are 10 outcomes for each.

Hence:

N = 4 \times 10^4 = 40000

Kami could create 40,000 codes that start with an even number.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

7 0
2 years ago
If the ratio of boys to girls in a class is 7:8 how many girls would be in class of 45 students?
Dafna11 [192]

Answer:

24 girls

Step-by-step explanation:

7 boys plus 8 girls is 15. 45 students / 15 = 3. 3 x 8 girls is 24.

5 0
3 years ago
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