(C) sin(-r) = -a
(D) sin(r) = -a
<u>Explanation:</u>
The unit circle definition allows us to extend the domain of sine and cosine to all real numbers. The process for determining the sine/cosine of any angle θ is as follows:
Starting from (1,0) move along the unit circle in the counterclockwise direction until the angle that is formed between your position, the origin, and the positive x-axis is equal to θ.
- sin θ is equal to the y-coordinate of your point, and
- cosθ is equal to the xxx-coordinate.
In the question, sin(-r) = -a and sin(r) = -a is equal to the x-coordinate, thus they are not correct.
An image is attached for reference.
<span>The curve equation y3 + 3yx - x3 = 9</span>
Differentiate implicitly with respect to x.
<span>3y2(dy/dx) + 3[y + x(dy/dx)] - 3x2 = 0</span>
<span>3y2(dy/dx) + 3y + 3x(dy/dx)] = 3x2</span>
<span>(dy/dx)(3y2 + 3x) = 3x2 - 3y</span>
<span>dy/dx = 3(x2- y)/3(y2 + x)</span>
<span>dy/dx = (x2- y)/(y2 + x)</span>
Answer: what is the question
Step-by-step explanation:
The -1 affects the coefficient of the entire term.
Without the -1,
the term has a positive coefficient.
(3a)² = 9a²
However, with the -1,
the term has a negative coefficient.
-(3a)² = -9a²