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3 years ago

Please answer this question..........

Mathematics

1 answer:

Umnica [9.8K]3 years ago

5 0

In order to find the y-intercept, replace x by 0.

So, for first option:
f(0) = 7(1) - 2 = 5

For second option:
f(0) = -3(1) - 5 = -8

For third option:
f(0) = 5(1)-1=4

For Fourth option:
f(0) = -5(1) + 10 = 5

For Fifth Option:
f(0) = 2(1) + 5 = 7

So, option 1 and 4 have the y-intercept (0,5)

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Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

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The complete question is

"Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real number solutions? (The related quadratic function will have two x-intercepts.) Check all that apply.

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The quadratic equations that have real number solutions are; 4x^2 – 3x – 1, and 2x^2 – 7x – 9.

<h3>What is the formula for Discriminant?</h3>

The formula for finding the discriminant is

$b^2 - 4ac$

The solution contains the term $\sqrt{b^2 - 4ac}$ which will be:

Real and distinct if the discriminant is positive

Real and equal if the discriminant is 0

Non-real and distinct roots if the discriminant is negative

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$b^2 - 4ac$

$= (-7) ^2 - 4( 2) ( -9)\\\\= 49 + 72 = 121$

This equation has two real number solutions.

For the quadratic equation $4x^ 2 - 3x- 1$

$b^2 - 4ac$

$= (-3) ^2 - 4( 4) ( -1)\\\\= 9 + 16 = 25$

This equation will have two real number solutions.

Learn more on discriminant here:

brainly.com/question/1537997

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Step-by-step explanation:

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