Answer:
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
That is z with a pvalue of 
, so Z = 1.645.
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 34.09 - 3.25 = 30.84.
The upper end of the interval is the sample mean added to M. So it is 34.09 + 3.25 = 37.34.
A 90% confidence interval for the mean number of letter sounds identified in one minute is: (30.84, 37.34).
21, 45, 121, 300, 312, 333, 347, 421, 614,
The median is the middle number of a data set therefore you need to arrange the data is order from smallest to largest as I have done above. Then you need to find the number in the middle which is 312 in this case by finding the number which has the central position (position 5 in this case) of the data set. If there are an even number of numbers in the data set, you add them together and divide by 2 though that is not necessary this time as there are an odd number of numbers.
Answer:
There is a 1/3 chance it lands on each section
Step-by-step explanation:
Answer:
9x9x9x9x9x9x9, theres your answer
