Question

The sum of three numbers is 108. The second number is 4 times the third. The first number is 6 more than the third. What are the numbers?

Answer 1

Answer:

The numbers are 23, 68 and 17.

Step-by-step explanation:

Given:

The sum of three numbers is 108.

The second number is 4 times the third.

The first number is 6 more than the third.

Now, to find the numbers.

Let the third number be $x$.

The second number be $4x$.

And the first number be $6+x$.

According to question:

$(6+x)+4x+x=108$

Now adding the variables we get:

⇒$6+6x=108$

Subtracting both sides by 6 we get:

⇒$6x=102$

Dividing both sides by 6 we get:

⇒$x=17.$

Third number =  $17.$

Second number =  $4x=4\times 17=68.$

First number = $6+x=6+17=23.$

Therefore, the numbers are 23, 68 and 17.