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Sphinxa [80]
3 years ago
5

In ΔKLM, the measure of ∠M=90°, the measure of ∠L=76°, and LM = 99 feet. Find the length of KL to the nearest tenth of a foot.

Mathematics
1 answer:
hram777 [196]3 years ago
7 0

Answer:

The length of KL is 409.2 foot

Step-by-step explanation:

Firstly, please check attachment for diagrammatic representation.

From the diagram, we can see that we are asked to calculate the value of the hypotenuse KL. Kindly note that the hypotenuse is the longest side of the right-angled triangle and it faces the angle 90 at all times.

Looking at what we have, we can see that we have adjacent and we are asked to calculate hypotenuse.

The trigonometric identity to use here is the Cosine

Cosine = length of adjacent/length of hypotenuse

cos 76 = 99/hypotenuse

hypotenuse = 99/cos76

hypotenuse = 99/0.24192

hypotenuse = 409.22 which is 409.2 to the nearest tenth of a foot

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The function h=-16t^2 +1700 gives you the height h, of an object in feet, at t seconds. How long will it take the object to hit
garik1379 [7]

Answer:

The object will hit the ground after 10.308 seconds.

Step-by-step explanation:

h(t) = -16t² + 1700

If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h(t) equal to 0 and solve.

-16t² + 1700 = 0   Plug this into a calculator if you have one.

t = -10.308 and t = 10.308

Since time can't be negative, your answer will be the positive value, 10.308.


6 0
3 years ago
Help pls this is my first question on here and I need help with this pls. I will give you the brainliest and a thanks!! :)) Can
docker41 [41]

Answer:

1. 18.85in

4. 25.13m

Step-by-step explanation:

I got you

So to find the circumference of any circle we use the equation 2pi(r)

2(3.1415)(3)= 18.85in for the first one because radius is half of the diameter which is 6 so half of 6 is 3

For 4. 4m is actually the radius so just plug that into the equation 2pi(4)=25.13m

4 0
3 years ago
F(x) = 1/x<br> g(x) = x - 4<br> Can you evaluate (gof)(0)? Explain why or why<br> not.
s344n2d4d5 [400]

(gof)(0) cannot be evaluated

<em><u>Solution:</u></em>

Given that,

f(x) = \frac{1}{x}\\\\g(x) = x - 4

A composite function is denoted by (g o f) (x) = g (f(x)).

The notation g o f is read as “g of f”

Therefore, let us find whether (gof)(0) can be evaluated or not

To find (gof)(0):

(g o f) (x) = g (f(x))

Now substitute the given value of f(x)

(g o f) (x) = g(\frac{1}{x})

\text{ Substitute } x = \frac{1}{x} \text{ in } g(x) = x - 4

(g o f) (x) = \frac{1}{x} - 4

Now to find (gof)(0), substitute x = 0

(g o f) (x) = \frac{1}{0} - 4

Since 1 divided by 0 is undefined, because any number divided by 0 is undefined

(gof)(0) cannot be evaluated

6 0
3 years ago
Read 2 more answers
Please help ♡♡♡♡♡♡♡​
lions [1.4K]

Step-by-step explanation:

\angle AOB and \angle BOC are linear pair angles.

\therefore m\angle AOB + m\angle BOC = 180° \\  \therefore  \: 3x + 124 \degree + 6x + 29 \degree  = 180° \\  \therefore  \: 9x  + 153 \degree  = 180°  \\ \therefore  \: 9x  = 180°  - 153 \degree   \\ \therefore  \: 9x  = 27 \degree   \\ \therefore  \:x =  \frac{27 \degree }{9}  \\  \huge \pink{ \boxed{\therefore  \:x =3 \degree }} \\  \\  \because \: m\angle BOC =6x + 29 \degree   \\ \therefore \: m\angle BOC =6 \times3 \degree + 29 \degree   \\ \therefore \: m\angle BOC = 18\degree + 29 \degree    \\ \\   \huge \red{ \boxed{\therefore \: m\angle BOC = 47 \degree   }}

5 0
3 years ago
i kind of know its C need 2nd opinion A tire manufacturer took a random sample of 50 tires and found that 3 were defective. In a
den301095 [7]

It's kind of not C.

Solve this proportion for 'x':

                                    3/50 = x/2400

Hint: Cross-multiply the proportion, then do what you need to do.

6 0
3 years ago
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