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Lapatulllka [165]
3 years ago
12

Please help me with this question im stuck on it for an hour im so confused i dont know how to do a but i can do b :)

Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0

96 m

2 m/sec²

Step-by-step explanation:

Step 1:

In a velocity and time graph , the area which is under the plotted line represents the distance traveled

In the given graph , the plotted line from t=0 to t=4 ( for the first 4 secs) is a   triangle with base = 4 and height = 8

Area of this triangle is (1/2) * b * h = (1/2)* 4*8 = 16 m

Step 2 :

The plotted line from t = 4 to t = 14 is a rectangle with length equal to 10 and breadth equal to 8

Hence its area = length * breadth = 10 * 8 = 80 m

Step 3 :

Total  distance traveled is 80 + 16 = 96 m

Step 4 :

In the velocity time graph , slope denotes the acceleration at any given time. Since we want the acceleration for the first 4 secs, we need to find  slope of  line in from t = 0 to t= 4

when t = 0, v =0 and t= 4, v = 8

Slope = 8-0/4-0 =2 m/sec²

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Answer:

y = |x-3| -1

Step-by-step explanation:

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6 0
3 years ago
If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the
denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.  

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)

Now at head wind → 720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)

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2a = 210

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⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

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