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2 years ago

Look at picture and help me answer pls

Mathematics

1 answer:

snow_lady [41]2 years ago

8 0

The answer is 112.5
Your welcome

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There are 14 white cabbages and x purple cabbages in a box.

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1 year ago

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borishaifa [10]

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3 years ago

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Assume ABC Company deposits $90,000 with First National Bank in an account earning interest at 6% per annum, compounded semi-ann

maw [93]

Answer:

Step-by-step explanation:

I'm goig to assume that the formula we need here is the following:

$A(t)=P(1+\frac{r}{n})^{(n)(t)$

where A(t) is the amount in the account after the compounding is done, n is the number of times per year the compounding occurs, r is the rate in decimal form, and t is the time in years. Filling in accordingly,

$A(t)=90000(1+\frac{.06}{2})^{(2)(5)}$ and simplifying a bit,

$A(t)=90000(1.03)^{10}$ and simplifying a bit more,

A(t) = 90000(1.343916379) so

the amount in the account after 5 years is

A(t) = 120,952.47

5 0

3 years ago

Given:

diamong [38]

Answer:

10-5 $\sqrt{2}$

Step-by-step explanation:

As per the attached figure, right angled $\triangle MDL$ has an inscribed circle whose center is $I$ .

We have joined the incenter $I$ to the vertices of the $\triangle MDL$ .

Sides MD and DL are equal because we are given that $\angle M = \angle L = 45 ^\circ.$

Formula for <em>area</em> of a $\triangle = \dfrac{1}{2} \times base \times height$

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10 $\sqrt{2}$

Points P,Q and R are at $90 ^\circ$ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of $\triangle$ MIL, $\triangle$ MID and $\triangle$ DIL.

Also,

$\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL$

$\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2$

So, radius of circle = $10-5\sqrt2$

8 0

2 years ago