Trying to find the missing segment to the triangle in the attached image.

Lucy is knitting a blanket and needs to buy some more yarn. At her local craft store, 2 skeins of yarn cost 57 and 8 skeins of y

prisoha [69]

Answer: it’s A 7/2 i just took this

Step-by-step explanation:

5 0

2 years ago

There are 45 new houses being built in a neighborhood Last month, 1/3 of them were sold. This month, 1/5 of the remaining houses

goldfiish [28.3K]

1/3 of 45 is 15.

So 45-15= 30.

1/5 of 30 is 6.

So 30-6=24.

There are 24 houses left to be sold.

7 0

3 years ago

Among us in real life

Vesnalui [34]

That would be scary lol but I guess kinda fun ❤️

3 0

2 years ago

Read 2 more answers

In a city, the distance between the library and the police station is 3 miles less than twice the distance between the police st

deff fn [24]

The distance between the police station and the fire station is x.
The distance between the library and the police station is 3 miles less than twice the distance between the police station and the fire station, so it is 2x-3. This distance is equal to 5 miles.

$2x-3=5 \\
2x=5+3 \\
2x=8 \\
x=\frac{8}{2} \\
x=4$

The police station and the fire station are 4 miles aparat.

5 0

3 years ago

Read 2 more answers

A researcher believes that the mean weight of competitive runners is about 140 pounds. A sample of 24 elite distance runners has

ExtremeBDS [4]

Answer:

$t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781$

$p_v =P(t_{(23)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=136$ represent the sample mean

$s=11$ represent the sample standard deviation

$n=24$ sample size

$\mu_o =140$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 140, the system of hypothesis would be:

Null hypothesis: $\mu \geq 140$

Alternative hypothesis: $\mu < 140$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=24-1=23$

Since is a one left tailed test the p value would be:

$p_v =P(t_{(23)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.

4 0

2 years ago