Answer:
B C D brainlest please
Step-by-step explanation:
x y
0 6
1 7
2 8
3 9
Answer:
As the picture shows, we have
V = (x+5)(x-2)x =30x
<=> x(x^2+3x-10) =30x
<=> x^3 + 3x^2-10x-30x = 0(*)
<=> x^3 +3x^2 -40x = 0
<=> x(x-5)(x+8) =0
Solve for (*), there are 3 solution :
5,
0(invalid),
-8(invalid)
=> 3 dimensions of rectangular box: 5, 3, 10
Answer:
Terrence's
Step-by-step explanation:
The length of the square that will be cut out is the height of the box.
1. a
Anya's method: 8.5 -1.5 =7, 11- 1.5 =9.5, the height is 1.5, so the volume is height x length x width which is 1.5 x 9.5 x 7 =99.75 squared inches.
Terrence's method: 8.5-3 = 5.5, 11-3 = 8. Vol= 5.5 x 8 x 3 =132 squared inches. 99.75 < 132 squared inches, Terrence's idea would create larger volume.
1. b
The box's size depends on the length/width/height of the cardboard being cut, which is why different measurements / cutting methods for the same size cardboard can result in different box sizes.
2. The square would be cut from all four corners, therefore the sum of the 2 squares on the cardboard cannot exceed the short side of the cardboard. The shorter side of the cardboard is 8.5 inches, divided by 2 = 4.25 inches, hence the squares cannot be larger than 4.25 inches. Keep in mind that if you cut exactly 4.25 inches you will have a strip of 2.5 inches width that cannot be turned into a box.
If you want to cut 5 inches squares out, depending on how you draw it, it would either overlap or go outside of the paper because 5+5 is ten, surely on the 11 inches side that would still be perfectly fine but for the 8.5 inches side, there isn't any room for the 10 inches.
The arrow is tilted to the right each time
