(5 + i)(4 - 2i)
20 - 10i + 4i - 2i²
20 - 6i - 2(-1)
20 - 6i + 2
20 + 2 - 6i
22 - 6i
In any function y = f(x) , set of all possible values of x define the domain of f(x), in the graph The curve in terms of x-axis(in 1st & 3rd quadrant) goes from -4 to -2(doesnt include -2).
So domain = [-4, -2)
Similarly, in 2nd and 4th quadrant, for x-axis
It goes from 2 to 5 (doesnt include 2 & 5)
So domain = (2, 5)
Hence,
Domain of the f(x) is [-4, -2) U (2, 5).
Range tells the possible values of y, for this function it goes from -5 to +3(doesnt include 3).
Range is [-5, 3)
The range of a function may refer to either of two closely related concepts: The codomain of the function The image of the function
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Answer:
Option C: 41
Step-by-step explanation:
<ABD+<CBD=90
<ABD=8x+1
<CBD=6x+5
(8x+1)+(6x+5)=90
Combine like terms
(8x+6x)+(1+5)=90
14x+6=90
14x=90-6
14x=84
divide both sides by 14
x=6
Now we plug that value into <DBC = 6x+5
6(6)+5=
36+5
41
