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3 years ago

The sum of three consecutive integers is 84. Find the integers If the smallest integer is x, the equation will be

Mathematics

1 answer:

lions [1.4K]3 years ago

7 0

The three consecutive integers are 26, 28, and 30. Hope this helps!

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PLEASE HELP WILL MARK BRAINIEST!!!!!!

vladimir1956 [14]

Answer:

Copy an angle is the best solution with compass and straight edge.

8 0

2 years ago

Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th

xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is $\bold{W=-3e^{7x}}$

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

$W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|$

Thus replacing the functions of the exercise we get:

$W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|$

Working with the determinant we get

$W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}$

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0

2 years ago

which is the factorization of x3 8? (x 2)(x2 – 2x 4) (x – 2)(x2 2x 4) (x 2)(x2 – 2x 8) (x – 2)(x2 2x 8)

kobusy [5.1K]

Hello,
+++++++++++++++++++++
Answer B

(x^3-2^3=(x-2)(x²+2x+4)
++++++++++++++++++++++

3 0

2 years ago

Read 2 more answers

Which expression is equivalent to the given expression? 17x−32x x(17−32) x(32−17) 17x(1−32) 17(x−32)

Scilla [17]

The answer would be 17(x-32)

7 0

2 years ago

If m is a common divisor of x and y, then x/y = (x ÷ k)/______

myrzilka [38]

Answer:

$\frac{x}{y} = \left(\frac{x}{y} \right)\cdot 1 = \left(\frac{x}{y}\right)\cdot \left(\frac{m}{m} \right) = \frac{\frac{x}{m} }{\frac{y}{m} }$

Step-by-step explanation:

The common divisor is the greatest natural number so that two or more natural numbers have no remainder. If $m$ is a common divisor of $x$ and $y$ , then $p = \frac{x}{m}$ and $q = \frac{y}{m}$ , where $p$ , $q$ $\in \mathbb{Z}$ . Then, we have the following expression:

$\frac{x}{y} = \left(\frac{x}{y} \right)\cdot 1 = \left(\frac{x}{y}\right)\cdot \left(\frac{m}{m} \right) = \frac{\frac{x}{m} }{\frac{y}{m} }$

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2 years ago