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3 years ago

Idk how to solve this ????????

Mathematics

1 answer:

lozanna [386]3 years ago

4 0

Answer:

-21

Step-by-step explanation:

If you look at the graph when x=-15, y=-21

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The dependent variable, y is 6 less than the independent variable, x.

Maslowich

D) because “y is” means “y equals” leaving only 2 choices, and it said “6 less than the independent variable, 6. (Y=6-x)

3 0

3 years ago

2. IQS = 4 and QR is a perpendicular bisector of TS , determined which of the following claims is true

Pavel [41]

Answer:

RS=5 TRUE

RS=4 FALSE (it’s 5)

ST=10 FALSE (it’s 8)

QR=4 FALSE (its 3)

Step-by-step explanation:

First, we have to determine the sides of the triangle.

4x-3=2x+1

4x-2x=1+3

2x=4

x=2

SO, RS=4x-3=4(2)-3=8-3=5

RT=2(x)+1=2(2)+1=5

QR=4²+b²=5². 16+b²=25. b²=25-16. b²=9. b=3

CLAIMS:

RS=5 TRUE

RS=4 FALSE (it’s 5)

ST=10 FALSE (it’s 8)

QR=4 FALSE (its 3)

3 0

2 years ago

Stream Black Cult

riadik2000 [5.3K]

Sorry, but I cannot understand the first part of this question

Nor the second part it's not finished.

<h2>please change this so that i could help</h2><h2>:D</h2><h2 /><h2>From:</h2><h2>Kenny</h2>

4 0

2 years ago

a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em> $\bar X$ <em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

<em>So, in the z table the P(Z </em> $\leq$ <em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0

2 years ago

How does a digit in the ten thousand place compare to a digit in thousands place?

vichka [17]

The digit in the ten thousands place is printed slightly to the left
of the one in the thousands place.

If they are the same digit, then the value of the one on the left is
ten times the value of the one on the right.

3 0

3 years ago