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Thepotemich [5.8K]
4 years ago
14

Henry sees 3 rabbits. Callie sees double that number of rabbits. How many rabbits does Callie see than Henry?

Mathematics
1 answer:
Effectus [21]4 years ago
3 0
3 times 2 = 6. So now that you know Callie saw 6 rabbits you know that she saw 3 more than Henry.
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Please help emergency
Firdavs [7]

Step-by-step explanation:

This is a probability related problem.

  Probability is the likelihood of an event to occur;

    Pr = \frac{number of possible outcomes}{Total sample space}

The sample space here is from 1 to 25 which is 25

A.

Pr of a card marked 8; we have just 1 possible outcome;

       Pr(8)  = \frac{1}{25}

B.

Pr  of drawing a card that is a multiple of 5;

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     Pr (multiples of 5) = \frac{4}{25}

C.

Pr of drawing a card with odd numbers:

          Number of odd numbers between 1 and 25  = 13

     Pr(odd numbers) = \frac{13}{25}

D.

Pr of drawing a number with square number on it;

        Square numbers between 1 and 25  = 1, 4, 9, 16 and 25

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3 0
3 years ago
PLS HELP
Umnica [9.8K]
The answer is 60, 60, 120, 120
do you go to rsm for geometry on saturday because i think i know you and this is exactly like the geometry homework 
8 0
4 years ago
Nickel-63 has half-life of about 96 years. after 336 years,about how many milligrams of an 800 mg sample will remain?
vagabundo [1.1K]
F=ar^t if the half-life is 96 years...

.5=r^96

ln(.5)=96lnr

ln(.5)/96=lnr

r=e^((ln.5)/96)

f=800e^(336(ln.5)/96)

f=70.71

So about 71mg will remain after 336 years.


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3 years ago
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natima [27]

Answer:

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Step-by-step explanation:

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How do you use the order of operations to evaluate expressions with exponents?
IgorLugansk [536]
Using BEDMAS, it would be brackets first, so anything Inside a set of brackets would be solved first, and would follow the same rule. Once the brackets have been solved, next would be the exponents. Since your brackets have been solved you can expand with the exponents. After exponents, would be anything that has to be divided or multiplied. These two operations are interchangeable based on what is more convenient or beneficial to do first. And lastly, addition and subtraction, which once again are interchangeable operations
5 0
3 years ago
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