Answer:
A. 3 cm
Step-by-step explanation:
The smallest face has the sides 4 cm and 8 cm. If the water is 4 cm from its top, then the height of the water is 
cm and the volume of the water is
The largest face has the sides 8 cm and 16 cm. If the container is placed on its largest face, then the volume of the water is
where h is the height of the water.
Equate volumes of the water:
Therefore, the water is 3 cm from the bottom.
Answer:
Positive numbers.
Step-by-step explanation:
Numbers after zero are positive numbers, which can be any number (whole or decimal/fraction). But numbers before zero are negative numbers which can be also whole or decimal fraction.
Example for numbers to the right of 0: 7, 6.5, 8/10
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<h3>I'm solving it using substitution method:-</h3>
<h3>7x+2y=3 {given}</h3>
<h3>=>7x=3-2y</h3>
<h3>=>x=(3-2y)/7-------(1)</h3>
<h3>x-3y=30 {given}</h3>
<h3>=>x=30+3y</h3>
<h3>=>(3-2y)/7=30+3y {putting the value of x from eqn 1}</h3>
<h3>=>3-2y=210+21y</h3>
<h3>=>3-210=21y+2y</h3>
<h3>=>-207=23y</h3>
<h3>=>y= -207/23= -9</h3>
<h3>putting the value of y on eqn(1):-</h3>
<h3>x=(3-2y)/7</h3>
<h3>x=>(3-2(-9))/7=(3+18)/7=21/7=3</h3>
<h2>Hence, x=3, y= -9</h2>
✌️✌️❤️❤️
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-6xy+11y
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Answer:
Since this is a linear (non-exponential) population problem you can just use the standard y=mx+b form of an equation. Where m = (change in population/change in years)
The numbers you were provided state that over the course of 7 years (1998-1991) the population increased by 420 people (4130-3710). So, (420/7) = 60 = m. Assuming that the growth rate for 1990 is the same as 1991. then you would have a starting population of (3710-60) or 3650, that would be your "b" value since at t=0 P(t) = 3650. This yields a final equation of P(t) = 60t +3650. Check the answer at t=1 and you get the population during 1991: 3710.
Step-by-step explanation:
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