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n200080 [17]
3 years ago
14

Find the area of a rectangle

Mathematics
2 answers:
vivado [14]3 years ago
4 0
To find the area of a rectangle multiply the length by the width
Alja [10]3 years ago
3 0
What are the measurements?
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A diagonal connects a vertex to another vertex without being a side of the polygon. There are 14 vertices in a 14-gon. This leaves 13 vertices left to connect to (since we cannot connect the vertex to itself). However, two of these vertices will form the sides of the 14-gon. This leaves us with 11 possible diagonals we can draw.
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Simplify the radical expression completely LaTeX: 3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}3 5 − 3 11 + 2 121 − 3 90 A. La
lora16 [44]

Answer:

3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}

Step-by-step explanation:

Given

3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}

Required

Simplify the expression

3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}

Express the square root of 121 as 11

3\sqrt{5}\:-\:3\sqrt{11}+2 * 11-3\sqrt{90}

3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{90}

Express 90 as 9 * 10

3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{9 * 10}

Split the surd to 2

3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{9} * \sqrt10}

Express the square root of 9 as 3

3\sqrt{5}\:-\:3\sqrt{11}+22-3 * 3 * \sqrt10}

3\sqrt{5}\:-\:3\sqrt{11}+22-9 * \sqrt10}

3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}

Hence, the result of the expression is

3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}

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3 years ago
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alexdok [17]

Answer:

<u>4</u><u>5</u><u>9</u><u>2</u><u>7</u><u>0</u>

  • <u>is</u><u> </u><u>the</u><u> </u><u>coefficient</u>
5 0
3 years ago
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