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n200080 [17]
3 years ago
14

Find the area of a rectangle

Mathematics
2 answers:
vivado [14]3 years ago
4 0
To find the area of a rectangle multiply the length by the width
Alja [10]3 years ago
3 0
What are the measurements?
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What number is 30% of 20%
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0.06 or you can just put 6.

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Here are two closed containers and four balls just fit into each container. Each ball has a diameter of 60mm. Which container ha
Studentka2010 [4]

Answer:

Container B has smaller surface area.

Step-by-step explanation:

Given:

Container A

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Height = 4 x 60 = 240 mm

Container B

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Height = 60

Computation:

Surface area of container A (Cylinder) = 2πr[h+r]

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Surface area of container A (Cylinder) = 67,885.70 mm² (Approx)

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Surface area of container B (Cuboid) = 2[(14,400)+(7,200)+(7,200)]

Surface area of container B (Cuboid) = 57,600 mm²

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8 0
3 years ago
What is the answer to this question I can’t work it out Ni=n02(yi-yo)/t2
mr_godi [17]

Changing the subject of an equation involves solving for another variable in the equation

The equation of t is t=\frac{\sqrt{y_i-y_o}}{N}

<h3>How to change the subject of the equation</h3>

The equation is given as:

N=\sqrt[2]{\frac{y_i-y_o}{t^2}}

Rewrite the equation as:

N=\sqrt{\frac{y_i-y_o}{t^2}}

Evaluate the square root of t^2

N=\frac{\sqrt{y_i-y_o}}{t}

Multiply both sides by t

Nt=\sqrt{y_i-y_o}

Make t the subject, in the above equation

t=\frac{\sqrt{y_i-y_o}}{N}

Hence, the equation of t is t=\frac{\sqrt{y_i-y_o}}{N}

Read more about subject of formula at:

brainly.com/question/657646

6 0
2 years ago
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Answer:

yr question is not here!!!!!!!!!!

6 0
2 years ago
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