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Ludmilka [50]
3 years ago
13

If a ladder reaches 10 feet up on a wall while the base is 3 feet away how tall is the ladder

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer:

Side a = 10.44031

Side b = 10

Side c = 3

Angle ∠A = 90° = 1.5708 rad = π/2

Angle ∠B = 73.301° = 73°18'3" = 1.27934 rad

Angle ∠C = 16.699° = 16°41'57" = 0.29146 rad

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Sally’s dance school had 60 students last year. This year there are only 48 students enrolled. By what percent did the enrollmen
Morgarella [4.7K]

Answer:

-20%

My brain is weird on how i figure it out but I divided 48 by 60 and got .80 so i just got the other whole to make it 1 so it is 20%. This is not the correct way to do this but this is how i got my answer.

8 0
3 years ago
Can someone help me on this
Vladimir79 [104]

Answer:

7%

Step-by-step explanation:

8 0
3 years ago
I need help with this question.
Valentin [98]

Answer:

x = 7.5

Step-by-step explanation:

A scale factor of 0.75 means all the dimensions are multiplied by 0.75. When the dimension 10 is multiplied by 0.75, it becomes ...

... x = 0.75 × 10 = 7.5

5 0
3 years ago
A circular mirror has a diameter of 12 inches. part a what is the area, in square inches, of the mirror?
vovangra [49]
1st part is c
2nd part is d 

I BELIEVE
6 0
3 years ago
List all possible rational roots. Then use synthetic division to confirm which rational roots exist:
Kisachek [45]

Answer:

\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term  and q is a factor of the leading coefficient.

\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

In your function, the constant term is -10 and the leading coefficient is 2, so

\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0
3 years ago
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