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3 years ago

14

Ted can rope a calf in 15 and 30 hundredths of a second randy can rope in his calf in 15 and 5 tenths of a second who was faster

?
1. ted
2. randy

1 answer:

Alisiya [41]3 years ago

3 0

Ted was faster by .2 seconds.

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A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

3 years ago

3(y−1.5)=9.9–4.2y Please help. Solve for y

AVprozaik [17]

Answer:

2

Step-by-step explanation:

8 0

3 years ago

A cockatoo costs $159.95. A cockatiel costs $48.85. What is the difference in price?

k0ka [10]

Answer:

111.1

use subtraction

8 0

3 years ago

Read 2 more answers

Find the sum of 49,529, and 308

bekas [8.4K]

You add 49,529 and 308

49,837

4 0

3 years ago

Which point is collinear with points a and d

Art [367]

B. (6, -8)

First, you need to figure out the slope of the line

(y1 - y2) / (x1 - x2)

After substituting points D(-3, 4) A(3, -4)

[4 - (-4)] / (-3 - 3)
(8) / (-6)

The slope of the line is -8/6 or -4/3 simplified

Then you can put it in point slope form:

(y - y1) = m(x - x1)

(y - y1) = -4/3(x - x1)

The point that I am using for point slope form is A(3, -4)

[y - (-4)] = -4/3(x - 3)
y + 4 = -4/3(x - 3)

Next you have to simplify the equation so that y is isolated

y + 4 = -4/3(x - 3)

First distribute the -4/3

y + 4 = -4/3(x) + (-4/3)(-3)
y + 4 = -4/3x + 4

Subtract 4 on both sides
y + 4 - 4 = -4/3x + 4 - 4
y = -4/3x

Now that you have y = -4/3x, you can substitute the values until one of them makes the equation equal

For example) (6, -8)
-8 = -4/3(6)
-8 = -8

So since (6, -8) fits in the slope intercept equation, it must me collinear with points A and D

~~hope this helps~~

6 0

3 years ago