The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
<h3>Which equation we get from the given condition?</h3>

 Where, we have
 d- the distance they can see in thousands
 h- their eye-level height in feet
 For Kaylib

 For Addison h=85(1/3)

Subtracting both distances we get

Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
 brainly.com/question/1392973
 
        
             
        
        
        
Let 1993 = time 0 = 0.  
Let 1999 = time 6 = 6  
Let 2012 = time 19 = 19  
So, a = 171 (million). First solve for k.  
176 = 171 e^k6  
176/171 = e^(k*6)  
ln (176/171) = 6k  
k = 1/6 ln (176/171)  
So, in 2012 we have: P(19) = 171 e^(19k), where k = 1/6 ln (176/171)
Hope this helped!
 
        
             
        
        
        
Answer:
-2x^2-6x-15
Step-by-step explanation: