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Elodia [21]
3 years ago
11

Can the probability of an event be greater than 1

Mathematics
1 answer:
kati45 [8]3 years ago
7 0
No. A probability of an even can not be greater than 1. It’s always in between 0 and 1 inclusive.
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A grocer pays $7.00 for each carton of 14 cantaloupes. Which inequality describes p, the set of prices, in dollars, that he can
Deffense [45]
I can tell you that is 50 cents for cantaloupe at that price....
So I think he'd have to charge $1.50. He'd get what he paid for back plus a dollar.   If C= one cantaloupe ....it would look something like
 p > $1.50c   
 BECAUSE 1.50 x 14 = 21 minus the 7 he paid would leave you with 14... on dollar per cantaloupe... so the price can be anything greater than $1.50
4 0
3 years ago
Read 2 more answers
Which one of the following statements is true?
dangina [55]

Answer:

C= to find x, add the given angles

Step-by-step explanation:

5 0
3 years ago
Find the indicated limit, if it exists.
Paha777 [63]
The limit is the y value that the graph approaches from both sides as x approaches the target limit

it they approach different values from the left and right sides, the limit does not exist

we want to find the limit as x approaches 5

we are given that f(x)=5-x for x<5 and f(5)=8 and f(x)=x+3 for x>5

evaluate them all for f(5)
f(x)=5-x
f(5)=5-5
f(5)=0

f(5)=8

f(x)=x+3
f(5)=5+3
f(5)=8

it approaches 0 and 8 from both sides
the limit doesn't exist
D
8 0
3 years ago
8x-6y=-20 -16x+7y=30
o-na [289]
<span>Simplifying 8x + -6y = -20

</span><span>Solving 8x + -6y = -20

</span><span>Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right

</span><span>Add '6y' to each side of the equation. 8x + -6y + 6y = -20 + 6y

</span><span>Combine like terms: -6y + 6y = 0 8x + 0 = -20 + 6y 8x = -20 + 6y
</span>
Divide each side by '8'. x = -2.5 + 0.75y


<span>Simplifying x = -2.5 + 0.75y</span>

8 0
3 years ago
Can someone please help me?
BabaBlast [244]

Answer:

3y^4/5x^6

Step-by-step explanation:

4 0
3 years ago
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