Given: 
Now factoring them,
Therefore, the answer to the question is 
Since they are FEWER than 30 total cones, the sum of x small cones and y large one must be LESS THAN 30: x+y <30
He needs AT LEAST a dozen (12), so that means that 12 will work or more than 12:
Step-by-step explanation:
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Heya friend,
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Let the digits at ones place be x. Then,
the digits at tens place = (8-x)
Original number = 10(8-x) + x
= 80 - 10x + x
= 80 - 9x
On interchanging the digits
new number obtained = 10x + 8-x
= 9x + 8
According to question,
New number - Original number = 18
9x + 8 - (80-9x) = 18
=> 9x + 8 - 80 + 9x = 18
=> 18x - 72 = 18
=> 18x = 18 + 72
=> 18x = 90
=> x = 90/18
=> x = 5
Hence, the digits at ones place is 5.
The digits at tens place = (8-5) = 3.
So, the original number is 35 and the new number is 53.
Thanks
1.Combine multiplied terms into a single fraction
2. Multiply by 1
3. Subtract 6 from both sides of the equation
4.Simplify
5.Subtract 3x from both sides of the equation
6.Simplify
7.Multiply all terms by the same value to eliminate fraction denominators
8.Simplify
9.Divide both sides of the equation by the same term
10.Simplify
Solution:x=4
