| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
(2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
Answer:
x<-1
Step-by-step explanation:
-4x+8>12
-4x>12-8
-4x>4
x>4/-4
x>-1
x<-1
Answer:
a=2
b=0
c=12
Step-by-step explanation:
The standard form of a quadratic equation is ax²+bx+c=0
Here's the given equation:
2x²+12=0
You might notice that the term bx is not there (there is just ax² and c). That means that b is 0.
The term 2x² is the term ax² in this equation. The coefficient in the term is 2, so that means that a is 2
12 has no variable, so that means it'll be c in the equation.
Hope this helps!
F(2y + 1) is 2
+
for this question
