Answer:
For less than 7 uniforms.
Step-by-step explanation:
The first company she called charges $70 per uniform.
So, the cost of x uniforms will be $70x.
The second company she called charges $280 plus $30 per uniform.
So, the cost of x uniform will be $(280 + 30x).
Now, if the total cost of purchasing x number of uniforms from the first company is less than that from the second company then, we can write the inequality equation as
70x < 280 + 30x
⇒ 70x - 30x < 280
⇒ 40x < 280
⇒ x < 7
Therefore, for less than 7 uniforms the cost from the first company will be less than the cost from the second company. (Answer)
Answer:
A
Step-by-step explanation:
30% of 30000 is 9000, 30000-9000=21000 (1 year)
30% of 21000 is 6300, 21000-6300=14700 (2 years)
30% of 14700 is 4410, 14700-4410= 10290 (3 years)
30% of 10290 is 3087, 10290-3097= 7203 (4 years)
30% of 7203 is 2160.9, 7203-2160.9= 5042.1 (5 years)
Answer:
- See attachment for table values
- y₁ = y₂ for x = 6
Step-by-step explanation:
In each case, put the x-value in the formula and do the arithmetic. If you're allowed, you can save some time and effort by realizing that the solution (x) will have to be an even number.
y₁ is an integer value for all integer values of x. y₂ is an integer value for even values of x only. y₁ and y₂ will both be integers (and possibly equal) only when x is even.
For example, for x = 6, we have
... y₁ = 3·6 - 8 = 18 -8 = 10
... y₂ = 0.5·6 +7 = 3 +7 = 10
That is, for x = 6, both columns of the table have the same number (10). That is, y₁ = y₂ for x = 6. The solution to the equation
... y₁ = y₂
is
... x = 6.
Answer:
55
Step-by-step explanation:
difference=8-5=3
if difference is 3 Cole bends=5 times
if difference is 33 Cole bends=(5/3)×33=55 times
Answer: 2(-2x+3)
Step-by-step explanation:
