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AleksAgata [21]
4 years ago
12

Find the GCF please help show your work 1. 25x^2 and 75x^3 2. 12x^2y and 18xy^2

Mathematics
1 answer:
andriy [413]4 years ago
6 0

Answer:

The probability would be 50%.

hope it helps :)  

can I have brainliest? I need it really bad.

Step-by-step explanation:

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write the six digit number that has the digit 4 in the thousands’ place, with each of the remaining digits being 3.
Rus_ich [418]
I’m pretty sure that the answer is 334333
6 0
3 years ago
True or false for each equation ​
kondor19780726 [428]

Answer:

1 - true ; 2 - false.

Step-by-step explanation:

The first equation is true as, if 4/2 is transcribed as -4/-2, the negatives would proceed to cancel out and provide the positive answer of 2.

The second equation is incorrect as the answer of positive 2 does not align with the negative numbers. Since it is 4/-2 instead of -4/-2, the negatives do not cancel out and it remains negative.

3 0
4 years ago
Read 2 more answers
A distribution of values is normal with a mean of 60 and a standard deviation of 16. From this distribution, you are drawing sam
professor190 [17]

Answer:

The interval containing the middle-most 76% of sample means is between 56.24 and 63.76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

A distribution of values is normal with a mean of 60 and a standard deviation of 16.

This means that \mu = 60, \sigma = 16

Samples of size 25:

This means that n = 25, s = \frac{16}{\sqrt{25}} = 3.2

Find the interval containing the middle-most 76% of sample means.

Between the 50 - (76/2) = 12th percentile and the 50 + (76/2) = 88th percentile.

12th percentile:

X when Z has a p-value of 0.12, so X when Z = -1.175.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-1.175 = \frac{X - 60}{3.2}

X - 60 = -1.175*3.2

X = 56.24

88th percentile:

Z = \frac{X - \mu}{s}

1.175 = \frac{X - 60}{3.2}

X - 60 = 1.175*3.2

X = 63.76

The interval containing the middle-most 76% of sample means is between 56.24 and 63.76.

3 0
3 years ago
98 points reward HELP!!!!
Aleksandr [31]

This gets smaller by 4 each time.  

The graph will show exponential decay.

5 0
3 years ago
Read 2 more answers
(x÷5) + (x÷3) = 8/15<br><br><br> Help please!
Tamiku [17]

x\div5=\dfrac{x}{5},\ x\div3=\dfrac{x}{3}\\\\(x\div5)+(x\div3)=\dfrac{8}{15}\\\\\dfrac{x}{5}+\dfrac{x}{3}=\dfrac{8}{15}\ \ \ \ \ |\cdot15\\\\15\cdot\dfrac{x}{5}+15\cdot\dfrac{x}{3}=15\cdot\dfrac{8}{15}\\\\3\cdot\dfrac{x}{1}+5\cdot\dfrac{x}{1}=1\cdot\dfrac{8}{1}\\\\3x+5x=8\\\\8x=8\ \ \ \ |:8\\\\\boxed{x=1}

6 0
4 years ago
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