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cupoosta [38]
3 years ago
15

A running track has a straight stretch that measures 200m at the ends there are

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0

Answer:

300.57 m

Step-by-step explanation:

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Solve 2x + 4 &gt; 16<br><br> A. x &gt; 10<br> B. x &lt; 6<br> C. x &lt; 10<br> D. x &gt; 6
Salsk061 [2.6K]

Hey there! :)

2x + 4 > 16

We're simply just trying to get x onto it's own side, so let's get rid of any numbers on the same side of it.

We can start out by subtracting both sides by 4.

2x + 4 - 4 > 16 - 4

Simplify.

2x > 12

Then, divide both sides by 2.

2x ÷ 2 > 12 ÷ 2

Simplify.

x > 6

Therefore, our answer is D. x > 6

~Hope I helped!~

6 0
3 years ago
If f(x)=7x, which of the following is the inverse of f(x)?
8090 [49]
The inverse is f¯¹(x)=x/7.
3 0
3 years ago
Read 2 more answers
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

-6

-6i

6i

6

Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

$ \sqrt{-4} = 2i $ .

Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $

$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
3 years ago
Will give brainliest
rosijanka [135]

Answer:

y = -6x

y = 4/5x - 1

8 0
3 years ago
Try to simplify 72/6+85/6
Reil [10]
72/6+ 85/6
= (72+ 85)/6
= 157/6
= (156+1)/ 6
= 156/6+ 1/6
= 26+ 1/6
= 26 1/6

The final answer is 26 1/6~
4 0
3 years ago
Read 2 more answers
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