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3 years ago

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If AC=3x, AB=15, and BC=2x-1, how could we solve for x? A. Set 3x=15 B. Set 3x=2x-1 C. Set 3x+15=2x-1 D. Set 3x=15+ (2x-1) E. No

t enough information

1 answer:

k0ka [10]3 years ago

5 0

Hmm this is a very challenging question good luck finding someone who can answer it lol

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The demand equation for a manufacturer's product is:

Juli2301 [7.4K]

From the given price function, we have;

(a) $\frac{dp}{dq} = - 13$

(b) The point elasticity of demand is 0.0256<u>;</u><u> </u><u>i</u><u>nelastic demand</u>

(c) $46.6

(d) Increase

<h3>How can the elasticity of demand be found?</h3>

a. The given function is presented as follows;

$p = 50 \times (151 - q) ^{0.02 \times \sqrt{q + 19} }$

Differentiating the above function with a graphing calculator and setting q = 150 gives;

$\frac{dp}{dq} = - 13$

b. The point elasticity of demand is given by the formula;

$e \: = \frac{dq}{dp} \times \frac{p}{q}$

When q = 150, we have;

P = 50

Which gives;

$e \: = \frac{1}{13} \times \frac{50}{150} = 0.0256$

The point elasticity of demand, <em>E </em>= <u>0.0256</u>

The <u>demand is inelastic</u> (less than 1) when the quantity demanded is 150 units

c. If the quantity demanded decreases from 150 to 140 units, we have;

$0.0256 \: = \frac{1}{13} \times \frac{p}{140} =$

Which gives;

p = 46.6

The price when the quantity demanded decreases to 140 is <u>$46.6</u>

d. Given that increase in price, from 46.6 to 50, increases the quantity demanded from 140 to 150, therefore;

The manufacturer should<u> increase the price</u>, <em>p </em>to increase the revenue, <em>R</em>.

R = p × q

Learn more about elasticity of demand here;

brainly.com/question/19141990

3 0

2 years ago

Simplify 3 radical 5 over 4 radical 5

matrenka [14]

3√5 / 4√5 The √5's cancel out

The answer is 3/4
This is because √5 is in both the denominator and the numerator, and so you can pull them both out.

8 0

3 years ago

Read 2 more answers

Subtract the sum of(8m-7n+6p)and(-3m-4-p)from the sum of (2m+4-3p)and(-m-n-p)

irinina [24]

8m,3n,9p would im guessing make the numbers to the rest of the problem

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3 years ago

write this equation into standered form and give me the key points ie ig a parabola the focus and vertex, if circle, center and

lions [1.4K]

Answer:

if you have the same answers as i had it would be the answer d

Step-by-step explanation:

7 0

3 years ago

India is the second most populous country in the world, with a population of over 1 billion people. Although the government has

aev [14]

Answer:

a) $P(X$

b) $P(X \geq 5)=P(X=5) +P(X=6) +P(X=7) +P(X=8)= 0.13+0.15+0.10+0.04=0.42$

c) $P(2 \leq X \leq 5)=P(x=2) +P(X=3) +P(X=4)+P(X=5)=0.12+0.18+0.24+0.13=0.67$

Step-by-step explanation:

For this case we have the following probability distribution function:

X P(X)

1 0.04

2 0.12

3 0.18

4 0.24

5 0.13

6 0.15

7 0.10

8 0.04

___________

Total 1.00

Part a

For this case we want this probability:

$P(X$

Part b

What is the probability that there are 5 or more members in a typical household in India? (Round your answer to 2 decimal places.)

For this case we want this probability:

$P(X \geq 5)=P(X=5) +P(X=6) +P(X=7) +P(X=8)= 0.13+0.15+0.10+0.04=0.42$

Part c

What is the probability that the number of members in a typical household in India is strictly between 2 and 5? (Round your answer to 2 decimal places.)

We want this probability:

$P(2 \leq X \leq 5)=P(x=2) +P(X=3) +P(X=4)+P(X=5)=0.12+0.18+0.24+0.13=0.67$

7 0

3 years ago