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vlada-n [284]
2 years ago
9

A cereal box has dimensions of 10 1/2 inches by 7 1/2 inches by 2 1/2 inches. What is the volume of the cereal box? 19 1/2 in³ 2

7 in³ 196 7/8 in³ 197 3/8 in³
Mathematics
1 answer:
Temka [501]2 years ago
5 0
196 3/8 in^3. To get this, multiply all the numbers together. To find volume, the equation is length x width x height.
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The average sunflower has 34 petals. What is the best estimate of the total number of petals on 57 sunflowers?
stellarik [79]
Your initial instinct would be to solve this problem with this solution. 34 x 57 = 1,938 petals.

However, the word estimate is present; therefore, we have to consider that we need to get the approximate number and not the exact number of petals.

There is a general rule regarding estimation or approximation. You have to round it to the nearest place you have based on. In this problem we round it off to the nearest tens place.

If the number is below 5, you round it down: 34 is rounded down to 30 petals.

If the number is above 5, you round it up: 57 is rounded up to 60 sunflowers.

Thus, your equation would be :  30 x 60 = 1,800 petals (best estimate)


3 0
3 years ago
2r = 72 please help me
noname [10]

you divide 72 by 2 to get r by itself and get 36


so r=36

6 0
3 years ago
Read 2 more answers
X/6 = 10/9<br> improper fraction in its simplified form
FinnZ [79.3K]

Answer:

\frac{x}{6}  =  \frac{10}{9}  \\   \therefore \: 9 \times x = 6 \times 10 \\ \therefore \:9x = 60 \\ \therefore \:x =  \frac{60}{9}  \\ \therefore \:x =  \frac{20}{3}  \\   \:  \:  \:  \:  \:  \: \huge \red{ \boxed{\therefore \:x =  6\frac{2}{3} }}

5 0
3 years ago
What is 55x690-20+438x129=? <br> I will give brainliest.
frosja888 [35]

Answer:

don't know it sorry about tht

7 0
3 years ago
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Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
1 year ago
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