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Finger [1]
3 years ago
8

K/4+3=14 solve for k?

Mathematics
2 answers:
BabaBlast [244]3 years ago
8 0

Answer:

k=44

Step-by-step explanation:

44/4=11+3=14

MissTica3 years ago
6 0

Answer:

k =44

Step-by-step explanation:

k/4+3=14

Subtract 3 from each side

k/4 +3-3 = 14-3

k/4 = 11

Multiply each side by 4

k/4 *4 = 11*4

k = 44

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Cody's Seafood House purchases
ankoles [38]

Answer:

Try this

Step-by-step explanation:

So what you have to do is turn 65% into a decimal. 65% as a decimal is 0.65.

Then what you want to do is divide 5.00 and 0.65 and see what you get.

8 0
3 years ago
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What is the inverse of the function f(x) = 2x – 10
BartSMP [9]

Answer:

y = 1/2x +5

Step-by-step explanation:

change f(x) to y

y = 2x - 10

then switch x and y

x = 2y - 10

then solve for y

add 10 to both sides and divide both sides by 2

6 0
3 years ago
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Write and solve a system of equations to determine how many tickets were sold before and at the music festival. PLEASE HELPPP
strojnjashka [21]

b = number of tickets sold before

a = number of tickets sold after

cost of a ticket = number of tickets times cost per ticket

before cost = 39.95b

after cost = 54.95a

total cost = 925000

39.95b + 54.95a = 925000

total number tickets = 20000

b + a = 20000

we have

39.95b + 54.95a = 925000

b + a = 20000

multiply second equation by -39.95 and add to first equation

39.95b + 54.95a = 925000

-39.95b-39.95a = -799000 +

0b+15a = 126000

15a = 126000

divide bot sides by 15

a = 8400

sub back

b + a = 20000

b+8400 = 20000

minus 8400 both sides

b = 11600

11,600 tickets sold before

8400 tickets sold after

3 0
3 years ago
A hypothesis will be used to test that a population mean equals 10 against the alternative that the population mean is more than
PilotLPTM [1.2K]

Answer:

A) 2.58

B) 1.96

C) 1.65

Step-by-step explanation:

A hypothesis used to test that

H_o : \mu  = 10

against the alternatives H1 : \mu not equal to 10

if null hypothesis is true, then distribution of test statics follow

Zo = \frac{\bar x - \mu}{\frac{\sigma}{\sqrt{n}}}

for two sided alternatives  hypothesis ( H1: \mu \neq 7), then P value is

P = 2[1- \phi(\left | Zc \right |)]                          (1)

a)significance level  \alpha = 0.01

from 1 eq we get

\pi (\left | Zc \right |) = P(Zo

Therefore  \left | Zc \right | = 2.58    FROM Z TABLE

B) significance level  \alpha = 0.05

from 1st equation we get

\pi (\left | Zc \right |) = P(Zo < \left | Zc \right |) = 1 - \frac{0.05}{2}  = 0.975

Therefore  \left | Zc \right | = 1.96    FROM Z TABLE

C) significance level  \alpha = 0.10

from 1 eq we get

\pi (\left | Zc \right |) = P(Zo

Therefore  \left | Zc \right | = 1.65    FROM Z TABLE

3 0
3 years ago
Please help I need this for a test
lianna [129]

Answer:

b

Step-by-step explanation:

cause

6 0
3 years ago
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