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densk [106]
4 years ago
9

For all real numbers a and b, if ab=0, then a=0 or b=0. True or false?

Mathematics
2 answers:
Sonbull [250]4 years ago
6 0
False I think because the variables are right next to each other which means it's multiplying and 0×0 equal 0
Alinara [238K]4 years ago
3 0
True. For example, if 2 is a, and b was 0, then ab would automatically be 0. Both a and b can be 0 though, but at least one of them must be zero.
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Solve the division problem using the area model strategy. Upload a picture or video to show your work.
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Step-by-step explanation:

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Marizza181 [45]
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3 years ago
Explain whether the following given sets are closed under addition:
Ivan

Answer:

Step-by-step explanation:

a) Yes.

\forall\ a,b\ \in\ B,\ a+b\in B\ (since\ 0+0=0)

b) Yes

W=\{0,1,2,3,..,\}\ (whole\ numbers)\\\forall\ a,b\ \in\ 3W,\ a+b\in 3W\\since:\\a\ \in\ 3W \Longrightarrow\ \exists\ k_1\in W | a=3*k_1\\\\b\ \in\ 3W \Longrightarrow\ \exists\ k_2\in W | b=3*k_2\\\\a+b=3*k_1+3*k_2=3*(k_1+k_2) \in 3W\\

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7 0
3 years ago
If line GH is perpendicular to line HJ, then GJ is ____ HJ.
valentinak56 [21]

Option A: >

Solution:

Given a triangle GHJ.

The line GH is perpendicular to line HJ.

This means the triangle is a right angled triangle.

In ΔGHJ, GH is the base of the triangle and

HJ is a height of the triangle.

Then the third side must be the hypotenuse of the right triangle.

We know that by the Pythagoras theorem,

(\text {Hypotenuse})^2=(\text{Base})^2+(\text{Height})^2

(\text {GJ})^2=(\text {GH})^2+(\text {HJ})^2

This clearly shows that the hypotenuse is greater than the height.

⇒ GJ > HJ

Option A: > is the correct answer.

If line GH is perpendicular to line HJ, then GJ is > HJ.

3 0
3 years ago
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Ksenya-84 [330]
4*3.14=12.56
h=12.56 this is the answer
7 0
3 years ago
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