All categories

3 years ago

If you brought a milkshake for 3.95 and paid for it with a 5 dollar bill,how much change would you receive ?

Mathematics

2 answers:

svp [43]3 years ago

5 0

The change received by you is $ 1.05

Solution:

Given that if you brought a milkshake for 3.95 and paid for it with a 5 dollar bill

To find: Change received by you

From given question

Price of milkshake = $ 3.95

Amount paid by you = $ 5

Therefore, change received by you is the difference between amount paid by you and price of milkshake

Change received by you = Amount paid by you - Price of milkshake

Change received by you = $ 5 - $ 3.95

Change received by you = 1.05

Thus change received by you is $ 1.05

OLEGan [10]3 years ago

5 0

Answer:

$1.05

Step-by-step explanation:

see the attached picture

You might be interested in

I do not know how to solve this problem or know what to do with the exponents

horsena [70]

K, remember
(ab)/(cd)=(a/c)(b/d) or whatever
also
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}= \frac{1}{x^m}$
and
$x^ \frac{m}{n}= \sqrt[n]{x^m}$
and
$( \frac{x}{y} )^m= \frac{x^m}{y^m}$
and
$(x^m)^n=x^{mn}$
and
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)

so
$( \frac{-7x^ \frac{3}{2} }{5y^4} )^{-2}$ =
$( \frac{-7}{5} )^{-2}( \frac{x^ \frac{3}{2} }{y^4} )^{-2}$ =
$( \frac{(-7)^{-2}}{5^{-2}} )( \frac{(x^ \frac{3}{2})^{-2} }{(y^4)^{-2}} )$ =
$( \frac{ \frac{1}{(-7)^2} }{ \frac{1}{5^2} } )( \frac{x^ \frac{-6}{2} }{y^{-8}} )$ =
$( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{(x^{-3}) }{\frac{1}{y^8}} )$
$( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{\frac{1}{x^3} }{\frac{1}{y^8}} )$ =
$(\frac{25}{49} )( \frac{y^8}{x^3}$ =
$\frac{25y^8}{49x^3}$

4 0

3 years ago

A customer gives you a $100 bill for a purchase that totals $22.75. What is the best money combination to give the $77.25 to the

Alinara [238K]

3, 20 bills 60 dollars add 1, 10 bill to get to 70 dollars add 1, 5 bill you get 75 dollars add 2,1 bills to get 77 dollars finaly 1 quarter to get 77 dollars and 25 cents

4 0

3 years ago

Read 2 more answers

D. 9.9 Math question please show work

34kurt

The ans is B
hope this helps

5 0

3 years ago

Focus Question: How do you determine whether a real-world context should be

Yakvenalex [24]

Answer:

Simplify the equation as closely as possible to the form of y = mx + b. Check to see if your equation has exponents. If it has exponents, it is nonlinear (exponential). If your equation has no exponents, it is linear.

3 0

2 years ago

Probability Questions Help is needed plzzzzzzzzzz

shtirl [24]

Answer: 0.0049 hope this is right

3 0

3 years ago