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3 years ago

12

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

t to y from the first equation is substituted into the second equation. 6x − y = 1 4x − 3y = −11

1 answer:

s344n2d4d5 [400]3 years ago

5 0

From the first equation
6x - y = 1
6x - y - 1 = 0
6x - 1 = y

Substituting we get
4x - 3(6x - 1) = -11

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) Three sides of a quadrilateral are the same length, q. The length of the fourth side is 7 inches.

Kruka [31]

Answer:

q=(40-7)/3 or simplified q=11

Step-by-step explanation:

So we know that the perimeter is 40 inches and one of the sides is 7 so logically we do 40-7 to get the length of the three remaining sides combined. Then to find the length q, we have to divide that answer by 3 because the three sides have the same length or (40-7)/3, which simplified is 11, so the length of the side is 11 inches and the expression is q=(40-7)/3.

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2 years ago

Find the length of the segment with endpoints of (3,2) and (-3,-6).

MakcuM [25]

The formula of the length of the segment AB:
$A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$
We have:
$A(3;\ 2)\to x_A=3;\ y_A=2\\\\B(-3;\ -6)\to x_B=-3;\ y_B=-6$
Substitute:
$|AB|=\sqrt{(-3-3)^2+(-6-2)^2}=\sqrt{(-6)^2+(-8)^2}\\\\=\sqrt{36+64}=\sqrt{100}=10$
Answer: B) 10.

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4 years ago

Radio signals travel at a rate of 3x10^8 meters per second how many seconds would it take for a radio signal to travel from a sa

marshall27 [118]

Answer:

1.2x10^-1 seconds

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Homework Jim Thompson! PART 2

BlackZzzverrR [31]

Problem 2

Part (a)

The 3D shape formed when rotating around the y axis forms a pencil tip

The shape formed when rotating around the x axis is a truncated cone turned on its side.

------------

Part (b)

Check out the two diagrams below.

============================================================

Problem 3

Answer: Choice A and Choice C

-----------------------

Explanation:

Think of stacks of coins. Let's say we had 2 stacks of 10 quarters each. The quarters are identical, so they must produce identical volumes. Those sub-volumes then add up to the same volume for each stack. Now imagine one stack is perfectly aligned and the other stack is a bit crooked. Has the volume changed for the crooked stack? No, it hasn't. We're still dealing with the same amount of coins and they yield the same volume.

For more information, check out Cavalieri's Principle.

With all that in mind, this leads us to choice C. If the bases are the same, and so are the heights, then we must be dealing with the same volumes.

On the other hand, if one base is wider (while the heights are still equal) then the wider based block is going to have more volume. This leads us to choice A.

6 0

2 years ago

The simplest form of the expression 4m-17/m^2-16 + 3m-11/m^2-16 has ____in the numerator and___ in the denominator.

lara31 [8.8K]

For this case we have the following expression:
$\frac{4m-17}{m^2-16} + \frac{3m-11}{m^2-16}$
Since the denominator is equal, then we can add the numerator.
We have then:
$\frac{(4m-17) + (3m-11)}{m^2-16}$
Adding similar terms we have:
$\frac{(4m+3m) + (-17-11)}{m^2-16}$
Rewriting we have:
$\frac{7m - 28}{m^2-16}$
Doing common factor in the numerator we have:
$\frac{7(m - 4)}{m^2-16}$
Factoring the denominator we have:
$\frac{7(m - 4)}{(m-4)(m+4)}$
Canceling similar terms we have:
$\frac{7}{m+4}$
Answer:
The simplest form of the expression has 7 in the numerator and m+4 in the denominator.

3 0

3 years ago