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3 years ago

12

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

t to y from the first equation is substituted into the second equation. 6x − y = 1 4x − 3y = −11

1 answer:

s344n2d4d5 [400]3 years ago

5 0

From the first equation
6x - y = 1
6x - y - 1 = 0
6x - 1 = y

Substituting we get
4x - 3(6x - 1) = -11

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A magician performing a magic act has asked for 2 volunteers from the audience to help with his routine. If there are 250 people

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The answer is 125. If you were to pair 250 people in 2, that would be 250 divided by 2. And 250 divided by 2 is 125.

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3 years ago

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Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

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3 years ago

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Alenkinab [10]

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3 years ago

Find the area of the figure. Round to the nearest TENTH.

Bad White [126]

Answer:

Step-by-step explanation:

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2 years ago

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Find the compound interest compounded annually on rupees 2700 rate 6 ⅔% per annum and time is 2 years

dalvyx [7]

<u>Answer:</u>

plz mark me as brainliest ...TOOK ME LONG TIME TO TYPE

answer = CI = 3108 RUPEES

<u>Step-by-step explanation:</u>

i am doing the method in which u find the simple interest of first year then second year.

SI FOR 1ST YEAR= P X R X T / 100

SI = 2700 X 20 X 2 / 3 X 100 ( RATE OF INTEREST IS 20 / 3)

SI = 108000/300

SI = 360

SI FOR SECOND YEAR =

P = 2700 + 360= 3060

SI = 3060 X 20 X 2 / 300

SI= 122400 / 300

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CI = 2700 + 408

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or u can solve be the method

CI = amount - principle

Amount= principle x (change in ratio) raised to time

***************************************

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3 years ago