You want to find out the probability of getting a 2 first and getting a 3 on a fair dice;
P(rolling 2 and 3)= (1/6)(1/6) <-- knowing that rolling a 2 has a possibility of 1/6, same with rolling a 3.
Therefore, the probability of getting a 2 and a three or 3 and a two is 1/36
Hope I helped :)
Answer:
Step-by-step explanation:
and 
does not have any common factor except for
C) because if you add up percents, it adds to 50%, or 0.5 or 1/2:
<span>Northeast 23%, Southwest 21%, Tulsa Metro 6%
</span>23 + 21 + 6 = 50
